From: Virgil on
In article
<bf42a4e2-9f0f-42a4-8bfe-2e884b633982(a)c33g2000yqm.googlegroups.com>,
WM <mueckenh(a)rz.fh-augsburg.de> wrote:

> But all that is not of interest for the present problem: All
> definable, computable, and somehow identifiable numbers and forms of
> numbers are within a countable set.

Once WM concedes any countably infinite set, as he does above, he has
lost the battle.
From: Virgil on
In article
<a3e6534b-2b79-447d-aa6b-da536824e31c(a)x27g2000yqb.googlegroups.com>,
WM <mueckenh(a)rz.fh-augsburg.de> wrote:

> On 16 Jun., 11:48, "|-|ercules" <radgray...(a)yahoo.com> wrote:
> > "WM" <mueck...(a)rz.fh-augsburg.de> wrote ...
> >
> >
> >
> > > By induction we prove: There is no initial segment of the (ANTI)diagonal
> > > that is not as a line in the list.
> >
> > Right, therefore the anti-diagonal does not contain any pattern of digits
> > that are not computable.
> >
> Sorry, you misquoted me. I wrote:
> By induction we prove: There is no initial segment of the diagonal
> that is not as a line in the list. And there is no part of the
> diagonal that is not in one single line of the list.
> But I have to excuse because I wrote somewhat unclear.
>
> The meaning is:
> 1) Every initial segment of the decimal expansion of pi is in at least
> one line of your list
> 3.
> 3.1
> 3.14
> 3.141
> ...
> What we can finde in the diagonal (not the anti-diagonal), namely
> 3.141 and so on, exactly that can be found in one line. This is
> obvious by construction of the list.
>
> 2) Every part of the diagonal is in at least one line. That means,
> every part is in one single line, or there are parts that are in
> different lines but not in one and the same.
>
> The latter proposition can be excluded.

How is the latter excluded?

Consider the sequence f(n) = trunc(pi*10^n)/10^n

While there are some successive lines which are equal
(where the decimal expansion of pi has 0 digits),
for every n there is an m, with n < m, such that f(n) < f(m) < pi.

> If there are more than one
> lines that contain parts of pi, then it can be proved, be induction,
> that two of them contain the same as one of them. This can be extended
> to three lines and four lines and so on for every n lines.

False for my example above.
>
> Hence we prove that all of pi, that is contained in at least one of
> the finite lines of your list, is contained in one single line.

False for my example above.

And equally false for f(n) = trunc(x*10^n)/10^n with any real x which
has a non-terminating decimal expansion.
From: WM on
On 16 Jun., 21:40, MoeBlee <jazzm...(a)hotmail.com> wrote:
> On Jun 16, 2:21 pm, MoeBlee <jazzm...(a)hotmail.com> wrote:
>
> > I don't have a thousand lifetimes to wait for you to show a
> > formula P such that both P and ~P are derivable in ZFC from the above
> > definition.
>
> CORRECTION: I should have said:
>
> [...] to show, for some formula P, a proof in ZFC (with said
> definition included) of P and a proof in ZFC (with said definition
> included)of ~P.

Look simply at the results.
If a theory says that there is an uncountable set of real numbers such
each number can be identified as a computable or definable or
constructable one, or in other ways, then this theory is provably
wrong.
Reason: Cantor either proves that a countable set is uncountable or
that a constructible/computable/definable number is not constructible/
computable/definable.
What the theory internally may be able to prove or not to prove is, at
least for my person, completely uninteresting.

Regards, WM
From: Virgil on
In article
<7399a634-9ad2-4c73-9c57-c26bf99a60cd(a)d8g2000yqf.googlegroups.com>,
WM <mueckenh(a)rz.fh-augsburg.de> wrote:

> This list is a list of everything.

Then it must list itself.
From: Virgil on
In article
<7a3e3a5a-2202-4cbb-9556-e3766ee5a745(a)k39g2000yqd.googlegroups.com>,
WM <mueckenh(a)rz.fh-augsburg.de> wrote:

> On 16 Jun., 17:55, Aatu Koskensilta <aatu.koskensi...(a)uta.fi> wrote:
> > WM <mueck...(a)rz.fh-augsburg.de> writes:
> > > It is very probable that every line has many different meaning, but no
> > > line has uncounatbly many meanings.
> >
> > Every line has an indefinite and indeterminate number of possible
> > meanings. It makes no sense to speak of the cardinality of the totality
> > of all possible meanings of a string of symbols.
>
> It is fact that all possible meanings must be defined by finite
> definitions. Therefore the meanings are countable. Therefore it makes
> sense to call the set of all meanings countable.

In proper set theory, one must be able to determine of an object whether
or not it is a member of a set, but since those vague "meanings" of a
string of symbols are so indeterminate, one cannot determine whether a
"meaning" does belong to a "symbol" so WM's "sets" are not well enough
defined to be sets in any proper set theory.
>
> In mathematics we can calculate or estimate things even if not all can
> be named.

But set membership must be less ambiguous than WM's.
> >
> > > Therefore the list contains only countably many finite definitions.

Except that it is not at all clear what has been listed.
> >
> > The list contains just random, meaningless strings. Whenever we instill,
> > with mathematical precision, these strings with some definite meaning,
> > so that they become definitions of reals, we find there are definitions
> > not included in the list. There is an absolute notion of computability
> > in logic.
>
> If this notion yields numbers only that are in trichotomy with each
> other, then the notion is acceptable. If this notion yields numbers
> like you gave examples for (IIRC) like n = (1 if Obama gets a second
> term and 0 otherwise) or so, then this notion together with your logic
> should be put into the trash can.

Only for a while.
>
> > There is no absolute notion of definability.
>
> We need not an absolute notion if we know that all possible
> definitions of the notion of definability belong to a countable set.

We cannot possibly know that.
>
> It is enough to prove by estimation that set theory is wrong. Compare
> the famous irrationality proofs and transcendence proofs of number
> theory. We need not calculate its deviation from truth to the fifth
> digit. It is enough to see that ZFC is wrong unless there is a natural
> between 0 and 1.

But what everyone else sees is that ZFC is right unless there is a
natural between 0 and 1.