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From: Abder-Rahman Ali on 13 Jul 2010 05:12 I'm trying to write a script such that when you enter a year, you get back a result of what occurred in this year or in the range of years, as follows: http://pastie.org/private/0nibq5i7abwghydfu0yzg The case is when I enter a year, I get the following: sub.rb:3: undefined method `what_were_you_doing_on' for main:Object (NoMethodError) But, the method is there. Why am I getting this? Thanks. -- Posted via http://www.ruby-forum.com/.
From: Stefano Crocco on 13 Jul 2010 05:21 On Tuesday 13 July 2010, Abder-Rahman Ali wrote: > |I'm trying to write a script such that when you enter a year, you get > |back a result of what occurred in this year or in the range of years, as > |follows: http://pastie.org/private/0nibq5i7abwghydfu0yzg > | > |The case is when I enter a year, I get the following: > | > |sub.rb:3: undefined method `what_were_you_doing_on' for main:Object > |(NoMethodError) > | > |But, the method is there. Why am I getting this? > | > |Thanks. Because you call the method (line 3) before defining it (line 6). Define the method before calling it and the error will disappear. Stefano
From: Peter Hickman on 13 Jul 2010 05:22 year == 2001..2006 means is the variable 'year' is a range starting with 2001 up to and including 2006 That is it expects that 'year' will be a range and not a fixnum. What you need is something like this if (2001..2006).include?(year)
From: Florian Gilcher on 13 Jul 2010 05:30 On Jul 13, 2010, at 11:12 AM, Abder-Rahman Ali wrote: > I'm trying to write a script such that when you enter a year, you get > back a result of what occurred in this year or in the range of years, as > follows: http://pastie.org/private/0nibq5i7abwghydfu0yzg > > The case is when I enter a year, I get the following: > > sub.rb:3: undefined method `what_were_you_doing_on' for main:Object > (NoMethodError) > > But, the method is there. Why am I getting this? > Order is important. The method definition has to be evaluated before calling it. If you put the call below the method definition, the call will work. Regards, Florian Gilcher
From: Abder-Rahman Ali on 13 Jul 2010 06:16 Thanks for your replies. I changed the script to look as follows: http://pastie.org/private/qwcmcpdzvxybm52s3ywxqg But, I ALWAYS get "Out of range...". Why is that? Thanks. -- Posted via http://www.ruby-forum.com/.
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