From: john1987 on

Hi,

Thanks for the reply but I am still unclear about this. I also have
another question that how much power I need on the primary coil that I
can get 300milliwatts out of the secondary coil.

John



On Jul 5, 9:58 pm, "Paul Hovnanian P.E." <P...(a)Hovnanian.com> wrote:
> john1987 wrote:
>
> > yes, watts / square meters
>
> So, why did you give us the diameter in inches? Who do you think we are?
> NASA?
>
> Dp-primary = 300 mWatts    power density in Watts per sq meters
>              ----------
>                Ap * K
>
> where Ap = primary (transmitter) coil area in meters^2 = 5.2E-4 for 1
> inch diameter
> and   K  = coupling coefficient
>
> --
> Paul Hovnanian     mailto:P...(a)Hovnanian.com
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