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From: john1987 on 6 Jul 2010 17:18 Hi, Thanks for the reply but I am still unclear about this. I also have another question that how much power I need on the primary coil that I can get 300milliwatts out of the secondary coil. John On Jul 5, 9:58 pm, "Paul Hovnanian P.E." <P...(a)Hovnanian.com> wrote: > john1987 wrote: > > > yes, watts / square meters > > So, why did you give us the diameter in inches? Who do you think we are? > NASA? > > Dp-primary = 300 mWatts power density in Watts per sq meters > ---------- > Ap * K > > where Ap = primary (transmitter) coil area in meters^2 = 5.2E-4 for 1 > inch diameter > and K = coupling coefficient > > -- > Paul Hovnanian mailto:P...(a)Hovnanian.com > ------------------------------------------------------------------ > Opinions stated herein are the sole property of the author. Standard > disclaimers apply. Celebrity voice impersonated. Batteries not included. > Limit one to a customer. Best if used by April 1, 2011. Refrigerate > after opening. Void if removed. |