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From: master1729 on 30 Nov 2009 04:24
let a b c d e f x y z be distinct positive integers.

a^5 + b^5 + c^5 = d^5 + e^5 + f^5 = x^5 + y^5 + z^5

solve that diophantine equation.

regards

tommy1729
From: 2.7182818284590... on 30 Nov 2009 15:35
What would this do for you? What can this do for you?
From: Gerry Myerson on 30 Nov 2009 16:51
In article
<1060668259.58373.1259609120702.JavaMail.root(a)gallium.mathforum.org>,
master1729 <tommy1729(a)gmail.com> wrote:

> let a b c d e f x y z be distinct positive integers.
>
> a^5 + b^5 + c^5 = d^5 + e^5 + f^5 = x^5 + y^5 + z^5
>
> solve that diophantine equation.

People may be interested to know that Swinnerton-Dyer gave
a parametric solution to a^5 + b^5 + c^5 = d^5 + e^5 + f^5
in Proc Camb Phil Soc 48 (1952) 516-518.

--
Gerry Myerson (gerry(a)maths.mq.edi.ai) (i -> u for email)
From: master1729 on 30 Nov 2009 07:59
Gerry Myerson wrote :

> In article
> <1060668259.58373.1259609120702.JavaMail.root(a)gallium.
> mathforum.org>,
> master1729 <tommy1729(a)gmail.com> wrote:
>
> > let a b c d e f x y z be distinct positive
> integers.
> >
> > a^5 + b^5 + c^5 = d^5 + e^5 + f^5 = x^5 + y^5 + z^5
> >
> > solve that diophantine equation.
>
> People may be interested to know that Swinnerton-Dyer
> gave
> a parametric solution to a^5 + b^5 + c^5 = d^5 + e^5
> + f^5
> in Proc Camb Phil Soc 48 (1952) 516-518.
>
> --
> Gerry Myerson (gerry(a)maths.mq.edi.ai) (i -> u for
> email)

yes the great Swinnerton-Dyer did so.

i knew he did , but it is good to post it.

hope it will help.

thanks

regards

tommy1729
From: master1729 on 1 Dec 2009 05:10
> let a b c d e f x y z be distinct positive integers.
>
> a^5 + b^5 + c^5 = d^5 + e^5 + f^5 = x^5 + y^5 + z^5
>
> solve that diophantine equation.
>
> regards
>
> tommy1729

cmon people , show me what you are made of !!
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