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From: Jean-Michel Pichavant on 10 Dec 2009 07:57
Guys,

I have some problem changing method locals with pdb:

import pdb

def test():
foo = 'foo'
pdb.set_trace()

test()
--Return--
> /home/jeanmichel/trunk/tnt/test.py(5)test()->None
-> pdb.set_trace()
(Pdb) print foo
foo
(Pdb) foo = 'bar'
(Pdb) print foo
foo
(Pdb)


I tried using locals() but it returns a copy of the locals. So changing
locals['foo'] won't do any good.
(Pdb) locals()
Out[6]: {'__return__': None, 'foo': 'foo'}


Any idea ? I'm starting to wonder if it is possible.

JM
From: Diez B. Roggisch on 10 Dec 2009 08:04
Jean-Michel Pichavant wrote:

> Guys,
>
> I have some problem changing method locals with pdb:
>
> import pdb
>
> def test():
> foo = 'foo'
> pdb.set_trace()
>
> test()
> --Return--
> > /home/jeanmichel/trunk/tnt/test.py(5)test()->None
> -> pdb.set_trace()
> (Pdb) print foo
> foo
> (Pdb) foo = 'bar'
> (Pdb) print foo
> foo
> (Pdb)
>
>
> I tried using locals() but it returns a copy of the locals. So changing
> locals['foo'] won't do any good.
> (Pdb) locals()
> Out[6]: {'__return__': None, 'foo': 'foo'}
>
>
> Any idea ? I'm starting to wonder if it is possible.

I recall having some issues with local variables sometimes, but actually
your example works fine for me:



def test():
foo = "foo"


import pdb; pdb.set_trace()

print foo

test()


And the session:

$ python /tmp/test.py
> /tmp/test.py(9)test()
-> print foo
(Pdb) pp foo
'foo'
(Pdb) foo = "bar"
(Pdb) n
bar
--Return--
> /tmp/test.py(9)test()->None
-> print foo
(Pdb) c


Diez
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