audio attenuator headphone to line
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From: Fred McKenzie on 11 Jul 2010 00:10 In article <4c390954$0$12156$fa0fcedb(a)news.zen.co.uk>, "tg" <nospam(a)nospameverever.net> wrote: > http://www.m-audio.com/images/global/manuals/MT11_flyerUK_LR.pdf TG- At the bottom of Key Features, a note reads: "For information on using dynamic mics with the MicroTrack II recorder, please visit the MicroTrack II product page on m-audio.com." This type of microphone apparently uses one of your 1/4" TRS inputs. I went to the web site and found the recorder's User Guide. Under Recording, it mentions that you should "2. Turn down the input gain of MicroTrack using the [LEVELS] buttons on the front panel." I think this may be enough to solve your problem of the headphone output being too 'heavy'. Fred
From: Dave Plowman (News) on 11 Jul 2010 04:33 In article <4c389aba$0$27995$db0fefd9(a)news.zen.co.uk>, tg <nospam(a)nospameverever.net> wrote: > I want to make a simple audio attenuator by soldering a couple of > resistors into a cable, similar to here: > http://www.epanorama.net/circuits/speaker_to_line.html this page talks > about attenuating speaker level down to line level with 10k and 1k but I > want to attenuate headphone level down to line level. I haven't done > this before and want to get it right so can anyone advise on the correct > resistor values to use? Replace that circuit temporarily with a 10K pot. Adjust the level to what you want. Measure both sides of the pot relative to the slider and make up a fixed attenuator to the same percentage values - the actual total load across the headphone output isn't critical. A total of 1-50K should be ok. -- *The closest I ever got to a 4.0 in school was my blood alcohol content* Dave Plowman dave(a)davenoise.co.uk London SW To e-mail, change noise into sound.
From: tg on 14 Jul 2010 15:31 thanks for all the replies here. I tried a few resistor combinations (from arfa's response) and what worked best in the end was a 22k resistor on the positive and a 47k resistor linking the positive and the negative. I made a cable with this setup and was able to get nice clean recordings from the headphone socket at normal headphone volume.
From: Arfa Daily on 14 Jul 2010 21:05 "tg" <nospam(a)nospameverever.net> wrote in message news:4c3e112d$0$28010$db0fefd9(a)news.zen.co.uk... > thanks for all the replies here. I tried a few resistor combinations (from > arfa's response) and what worked best in the end was a 22k resistor on the > positive and a 47k resistor linking the positive and the negative. I made > a cable with this setup and was able to get nice clean recordings from the > headphone socket at normal headphone volume. I'm glad what I said helped you to get a result that you were pleased with, but I'm a little confused. Are you sure that the resistor values that you've stated are correct, and the bottom one wasn't 4.7k rather than 47k ? As stated, the attenuation provided would be very small - in example numbers, 1v in, around 0.7v out. With the bottom resistor at 4.7k, the attenuation would be something over 4 : 1, which seems more realistic ? Arfa
From: tg on 15 Jul 2010 15:29
"Arfa Daily" <arfa.daily(a)ntlworld.com> wrote in message news:79t%n.190989$vB5.75730(a)hurricane... > I'm glad what I said helped you to get a result that you were pleased > with, but I'm a little confused. Are you sure that the resistor values > that you've stated are correct, and the bottom one wasn't 4.7k rather than > 47k ? <snip> nope, just checked and the bottom resistor is 47K. in your previous post you did say 'a ratio of 2 : 1 might be more appropriate,' and you were right, this - as it turned out - is a 2:1 ratio. |