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From: master44 on 7 Jan 2010 19:04
I looking to write a bash shell script to parse a log file for the
first occurance of a date and then once that date is found, the
contents of the rest of the log file will be copied to a new file.

Here is a simplified example of a log file (test.log)

2010-01-05 ....
2010-01-06 ....
2010-01-07 ....
2010-01-07 ....
2010-01-07 ....

So for example I want to search for the first occurance of 2010-01-07
and then copy the rest of the file to anther file (test2.log)

So the new file (test2.log) would look like this:

2010-01-07 ....
2010-01-07 ....
2010-01-07 ....

I am thinking this can be done with sed and I have tried the
following, but something is off...

grep "2010-01-07|sed 's/^0//g'`" test.log|tail +2|head -1 > test2.log

If anyone has done this before or has any ideas, I'd appreciate it!

Thanks







From: Kevin Collins on 7 Jan 2010 20:14
On 2010-01-08, master44 <trpost(a)gmail.com> wrote:
> I looking to write a bash shell script to parse a log file for the
> first occurance of a date and then once that date is found, the
> contents of the rest of the log file will be copied to a new file.
>
> Here is a simplified example of a log file (test.log)
>
> 2010-01-05 ....
> 2010-01-06 ....
> 2010-01-07 ....
> 2010-01-07 ....
> 2010-01-07 ....
>
> So for example I want to search for the first occurance of 2010-01-07
> and then copy the rest of the file to anther file (test2.log)
>
> So the new file (test2.log) would look like this:
>
> 2010-01-07 ....
> 2010-01-07 ....
> 2010-01-07 ....
>
> I am thinking this can be done with sed and I have tried the
> following, but something is off...
>
> grep "2010-01-07|sed 's/^0//g'`" test.log|tail +2|head -1 > test2.log
^^
You need to tell grep the file name - you are combining the grep into your sed
command!

> If anyone has done this before or has any ideas, I'd appreciate it!

Using perl, you could do:

perl -ne '$cnt++ if (/^2010-01-07 /); print if ($cnt)' test.log > test2.log

Kevin
From: Ed Morton on 7 Jan 2010 20:37
On 1/7/2010 6:04 PM, master44 wrote:
> I looking to write a bash shell script to parse a log file for the
> first occurance of a date and then once that date is found, the
> contents of the rest of the log file will be copied to a new file.
>
> Here is a simplified example of a log file (test.log)
>
> 2010-01-05 ....
> 2010-01-06 ....
> 2010-01-07 ....
> 2010-01-07 ....
> 2010-01-07 ....
>
> So for example I want to search for the first occurance of 2010-01-07
> and then copy the rest of the file to anther file (test2.log)
>
> So the new file (test2.log) would look like this:
>
> 2010-01-07 ....
> 2010-01-07 ....
> 2010-01-07 ....
>
> I am thinking this can be done with sed and I have tried the
> following, but something is off...
>
> grep "2010-01-07|sed 's/^0//g'`" test.log|tail +2|head -1> test2.log
>
> If anyone has done this before or has any ideas, I'd appreciate it!
>

sed is an excellent tool for simple substitutions on a single line, for anything
else use awk, perl, etc. In this case:

awk '/2010-01-07/,0' test.log > test2.log

Ed.
From: Seebs on 7 Jan 2010 20:18
On 2010-01-08, master44 <trpost(a)gmail.com> wrote:
> I looking to write a bash shell script to parse a log file for the
> first occurance of a date and then once that date is found, the
> contents of the rest of the log file will be copied to a new file.

sed -n -e '/2010-01-07/,$p'

-s
--
Copyright 2010, all wrongs reversed. Peter Seebach / usenet-nospam(a)seebs.net
http://www.seebs.net/log/ <-- lawsuits, religion, and funny pictures
http://en.wikipedia.org/wiki/Fair_Game_(Scientology) <-- get educated!
From: Bill Marcum on 7 Jan 2010 20:36
On 2010-01-08, master44 <trpost(a)gmail.com> wrote:
>
> So for example I want to search for the first occurance of 2010-01-07
> and then copy the rest of the file to anther file (test2.log)
>
> So the new file (test2.log) would look like this:
>
> 2010-01-07 ....
> 2010-01-07 ....
> 2010-01-07 ....
>
> I am thinking this can be done with sed and I have tried the
> following, but something is off...
>
> grep "2010-01-07|sed 's/^0//g'`" test.log|tail +2|head -1 > test2.log
>
> If anyone has done this before or has any ideas, I'd appreciate it!
>
sed -n '/2010-01-07/,$p' test.log >test2.log
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