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From: maria giovanna dainotti on 2 Jul 2010 02:54
Dear Math Group,
I have the following problem when I do a contourplot I can't use
the boolean variabile. This is the function for which I would like
to have the contours

R1=1.029
R2=2.92
R3=20
e1=300
e2=1
e3=100
i=pi/12

�ContourPlot[2*R3*Sin[ArcCos[Re[x/R3]]]*e3+2*R2/Cos[i]*Sin[ArcCos[Re[x/2.92]]]*(e2-e3)+2*R1/Cos[i]*Sin[ArcCos[Re[x/R1]]]*(e1-e2),(2*R3*Sin[ArcCos[Re[x/R3]]]*e3+2*R2/Cos[i]*Sin[ArcCos[Re[x/R2]]]*(e2-e3))*(Boole[-R2<x<-R1]+Boole[R2>x>R1]),2*R3*Sin[ArcCos[Re[x/R3]]]*e3*(Boole[x<-R2]+Boole[x>R2])+R3*Cos[ArcSin[y/R3]],{x,-2,2 },{y,-20,20}]


Thanks a lot for your help
Maria
From: Leonid Shifrin on 2 Jul 2010 07:27
Hi Maria,

First, your <pi> in <i==pi/12> must be <Pi>, I guess. Then, you list several
functions separated by a comma, and ContourPlot does not understand. This
works, for instance:

ContourPlot[
2*R3*Sin[ArcCos[Re[x/R3]]]*e3 +
2*R2/Cos[i]*Sin[ArcCos[Re[x/2.92]]]*(e2 - e3) +
2*R1/Cos[i]*Sin[ArcCos[Re[x/R1]]]*(e1 - e2), {x, -2, 2}, {y, -20,
20}]

What did you mean by separating functions with a comma - what did you try to
achieve? Knowing this it would be easier to help.

Regards,
Leonid


On Thu, Jul 1, 2010 at 11:54 PM, maria giovanna dainotti <
mariagiovannadainotti(a)yahoo.it> wrote:

> Dear Math Group,
> I have the following problem when I do a contourplot I can't use
> the boolean variabile. This is the function for which I would like
> to have the contours
>
> R1==1.029
> R2==2.92
> R3=
> e1==300
> e2==1
> e3==100
> i==pi/12
>
> ContourPlot[2*R3*Sin[ArcCos[Re[x/R3]]]*e3+2*R2/Cos[i]*Sin[ArcCos[Re[x/2.=
92]]]*(e2-e3)+2*R1/Cos[i]*Sin[ArcCos[Re[x/R1]]]*(e1-e2),(2*R3*Sin[ArcCos[Re=
[x/R3]]]*e3+2*R2/Cos[i]*Sin[ArcCos[Re[x/R2]]]*(e2-e3))*(Boole[-R2<x<-R1]+Bo=
ole[R2>x>R1]),2*R3*Sin[ArcCos[Re[x/R3]]]*e3*(Boole[x<-R2]+Boole[x>R2])+R3*C=
os[ArcSin[y/R3]],{x,-2,2
> },{y,-20,20}]
>
>
> Thanks a lot for your help
> Maria
>
From: Peter Pein on 3 Jul 2010 08:17
Am Fri, 2 Jul 2010 06:54:31 +0000 (UTC)
schrieb maria giovanna dainotti <mariagiovannadainotti(a)yahoo.it>:

> Dear Math Group,
> I have the following problem when I do a contourplot I can't use
> the boolean variabile. This is the function for which I would like
> to have the contours
>
> R1=1.029
> R2=2.92
> R3
> e1=300
> e2=1
> e3=100
> i=pi/12
>
> =C2 ContourPlot[]==0==Im[y,{x,-2,2 },{y,-20,20}]
>
>
> Thanks a lot for your help
> Maria

Hi Maria,

1.) pi is just any variable; I guess you want Pi (with capital P) and
the Re[] around x/"real valued constant" is superfluous.
2.) what exactly do you expect from a call to Contourplot with three
expressions (not wrapped by a list). Did you want ParametricPlot3D
(which looks quite boring). Are the three expressions part of a vector
and you want the norm? That would lead to a few vertical stripes.
3.) It could speed thing up to throw FullSimplify once onto the
expression(s) to be plotted:
In[1]:= R1=1029/1000;
R2=292/100;
R3;
e1=300;
e2=1;
e3=100;
i=Pi/12;
vec=FullSimplify[{
2*R3*Sin[ArcCos[Re[x/R3]]]*e3+2*R2/Cos[i]*Sin[ArcCos[Re[x/R2]]]*(e2-e3)+2*R=
1/Cos[i]*Sin[ArcCos[Re[x/R1]]]*(e1-e2),(2*R3*Sin[ArcCos[Re[x/R3]]]*e3+2*R2/=
Cos[i]*Sin[ArcCos[Re[x/R2]]]*(e2-e3))*(Boole[-R2<x<-R1]+Boole[R2>x>R1]),2*R=
3*Sin[ArcCos[Re[x/R3]]]*e3*(Boole[x<-R2]+Boole[x>R2])+R3*Cos[ArcSin[y/R3]]}=
,{x,y}\[Element]Reals]

Out[8]= {200 Sqrt[400-x^2]+(299 Sqrt[1058841-1000000 x^2]-3960
Sqrt[5329-625 x^2])/(125 (Sqrt[2]+Sqrt[6])),4/25 (1250 Sqrt[400-x^2]-99
Sqrt[(-2+Sqrt[3]) (-5329+625 x^2)])
(Boole[73/25>x>1029/1000]+Boole[-(73/25)<x<-(1029/1000)]),Sqrt[400-y^2]+200
Sqrt[400-x^2] (Boole[25 x>73]+Boole[x<-(73/25)])}

Peter

P.S.: Claws-Mail opened this again; maybe I forgot to send it maybe
this posting comes twice. In the latter case: my apologies to the brave
moderator.


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