calculating an acceleration
in [Matlab]
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From: Luca Turchet on 10 May 2010 05:13 Hi all, I need an help to calculate an acceleration between 2 points: acc = (s2-s1)/[(t2-t1)^2]; % meters/seconds^2 These are the known parameters: s2 - s1 = distance; % meters v1 % velocity at time t1, meters/seconds v2 % velocity at time t2, meters/seconds function to calculate v2 knowing v1: v(t) = v(t-1)*exp(-0.1) In our case is v2 = v1*exp(-0.1); Any suggestion please? Do you think it is possible to calculate the acceleration having only these known parameters? Thanks in advance Best
From: Rune Allnor on 10 May 2010 06:06 On 10 Mai, 11:13, "Luca Turchet" <t...(a)imi.aau.dk> wrote: > Hi all, > I need an help to calculate an acceleration between 2 points: > > acc = (s2-s1)/[(t2-t1)^2]; % meters/seconds^2 > > These are the known parameters: > > s2 - s1 = distance; % meters > > v1 % velocity at time t1, meters/seconds > v2 % velocity at time t2, meters/seconds > > function to calculate v2 knowing v1: > > v(t) = v(t-1)*exp(-0.1) > > In our case is v2 = v1*exp(-0.1); > > Any suggestion please? > > Do you think it is possible to calculate the acceleration having only these known parameters? No, it isn't. You have some additional known relations that you haven't listed: a(t) = dv(t)/dt = d^2s(t)/dt^2. Use these relations (or the corresponding integrals) to work out the relation between v(t) and s(t), and insert in the formulas you have been given. Rune
From: Riccardo on 10 May 2010 07:00 "Luca Turchet" <tur(a)imi.aau.dk> wrote in message <hs8in1$k0k$1(a)fred.mathworks.com>... > Hi all, > I need an help to calculate an acceleration between 2 points: > > acc = (s2-s1)/[(t2-t1)^2]; % meters/seconds^2 > > > > These are the known parameters: > > s2 - s1 = distance; % meters > > v1 % velocity at time t1, meters/seconds > v2 % velocity at time t2, meters/seconds > > > function to calculate v2 knowing v1: > > v(t) = v(t-1)*exp(-0.1) > > In our case is v2 = v1*exp(-0.1); > > > Any suggestion please? > > Do you think it is possible to calculate the acceleration having only these known parameters? > > Thanks in advance > > Best The answer depends on whether you can apply the constant acceleration kinematics equations or not. If you can, then acc = F(s1, s2, v1, v2). If you cannot, then s1, s2, v1, v2 may only allow you to compute an average acceleration between s1 and s2.
From: Luca Turchet on 10 May 2010 07:42 Hi, thanks a lot for the answer. I knew the relation a(t) = dv(t)/dt = d^2s(t)/dt^2 My question is : having v(t) = v(t-1)*exp(-0.1) the acceleration, i.e. the derivative of the acceleration shold be dv(t)/dt = exp(-0.1) Is it correct? Could you please enlight me? Thanks > > Do you think it is possible to calculate the acceleration having only these known parameters? > > No, it isn't. > > You have some additional known relations that you haven't listed: > > a(t) = dv(t)/dt = d^2s(t)/dt^2. > > Use these relations (or the corresponding integrals) to work > out the relation between v(t) and s(t), and insert in the > formulas you have been given. > > Rune
From: Luca Turchet on 10 May 2010 07:46
Hi Riccardo, thanks for your answer. > The answer depends on whether you can apply the constant acceleration kinematics equations or not. If you can, then acc = F(s1, s2, v1, v2). Yes the acceleration is constant. What do you mean with F? I am searching this formula. Could you please give me an example? ....I don´t understand clearly, sorry :-( Help! Thanks Best |