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From: Archimedes Plutonium on 11 Jul 2010 23:16 Archimedes Plutonium wrote: > Due to a conversation with a journal editor, my interest has been > rekindled in a proof of the Infinitude of Twin Primes and all even > numbered pairs of primes. The reason this attempt works, I feel, is > that I have eliminated the regular primes out of the picture by a > clever devise that was used in the Direct method of the > square root to eliminate factors. > > XXXXXX > Euclid's Infinitude of Primes proof, Direct or constructive in short- > form goes like this: > 1) Definition of prime > 2) Given any finite set of primes > 3) Multiply the lot and add 1 (Euclid's number) which I call W+1 > 4) Either W+1 is prime or we conduct a prime factor search > 5) this new prime increases the set cardinality by one more prime > 6) since this operation of increasing set cardinality occurs for > any > given finite set we start with, means the primes are infinite set. > > XXXXXX > > Euclid Infinitude of Primes proof, Indirect in > short- > form goes like this: > > > 1) Definition of prime > 2) Hypothetical assumption, suppose set of primes 2,3,5,7,.. is > finite with P_k the last and final prime > 3) Multiply the lot and add 1 (Euclid's number) which I call W+1 > 4) W+1 is necessarily prime > 5) contradiction to P_k as the last and largest prime > 6) set of primes is infinite. > > XXXXXX > > DIRECT Method (constructive method), long-form; Infinitude of Primes > Proof > > > (1) Definition of prime as a positive integer divisible > only by itself and 1. > > > (2) Statement: Given any finite collection of primes > 2,3,5,7,11, ..,p_n possessing a cardinality n Reason: given > > > (3) Statement: we find another prime by considering W+1 =(2x3x...xpn) > +1 Reason: can always operate on given numbers > > > (4) Statement: Either W+1 itself is a prime Reason: Unique Prime > Factorization theorem > > > (5) Statement: Or else it has a prime factor not equal to any of the > 2,3,...,pn > Reason: Unique Prime Factorization theorem > > > (6) Statement: If W+1 is not prime, we find that prime factor Reason: > We take the square root of W+1 and we do a prime search through all > the primes from 2 to > square-root of W+1 until we find that prime factor which > evenly divides W+1 > > > (7) Statement: Thus the cardinality of every finite set can be > increased. Reason: from steps (3) through (6) > > > (8) Statement: Since all/any finite cardinality set can be increased > by one more prime, therefore the set of primes is an infinite set. > Reason: going from the existential logical quantifier to the > universal > quantification > > XXXXXX > > INDIRECT (contradiction) Method, Long-form; Infinitude of Primes > Proof > and > the numbering is different to show the reductio ad absurdum > structure > as > given by Thomason and Fitch in Symbolic Logic book. > > > (1) Definition of prime as a positive integer divisible > only by itself and 1. > > > (2) The prime numbers are the numbers 2,3,5,7,11, ..,pn,... of set S > Reason: definition of primes > > > (3.0) Suppose finite, then 2,3,5, ..,p_n is the complete series set > with p_n the largest prime Reason: this is the supposition step > > > (3.1) Set S are the only primes that exist Reason: from step (3.0) > > > (3.2) Form W+1 = (2x3x5x, ..,xpn) + 1. Reason: can always operate and > form a new number > > > (3.3) Divide W+1 successively by each prime of > 2,3,5,7,11,..pn and they all leave a remainder of 1. > Reason: unique prime factorization theorem > > > (3.4) W+1 is necessarily prime. Reason: definition of prime, step > (1). > > > (3.5) Contradiction Reason: pn was supposed the largest prime yet we > constructed a new prime, W+1, larger than pn > > > (3.6) Reverse supposition step. Reason (3.5) coupled with (3.0) > > > (4) Set of primes are infinite Reason: steps (1) through (3.6) > > XXXXXX > > > For years now I thought I had not delivered a proof of the Infinitude > of Twin Primes, that somehow I came up > short, but due to a email conversation, I realized that > all along I had proven the Infinitude of Twin, Quad, 6th primes > and all other even multiples Primes. > > The proof is only Indirect method because only in the Indirect are you > ensured of two new primes. > > Let me show you the Indirect Regular Primes Infinitude proof with a > number example: > > > Euclid Infinitude of Primes proof, Indirect in > short- form with number example of 3 and 5 : > > > 1) Definition of prime > 2) Hypothetical assumption, suppose set of primes 3,5 are all the > primes that exist with 5 the largest prime > 3) Multiply the lot and add 1 (Euclid's number) which is (3x5) +1 = > 16 > 4) 16 is necessarily prime due to (1) and the assumptive step > 5) contradiction to 5 as the last and largest prime > 6) set of primes is infinite. > > That number example is what delivers a valid Infinitude of Twin > Primes, Quad Primes, 6th Primes, etc etc. > > XXXXXX > > Proof of the Infinitude of Twin Primes: > > INDIRECT (contradiction) Method, Long-form; Infinitude of Twin Primes > > > (1) Definition of prime as a positive integer divisible > only by itself and 1. > > > (2) The prime numbers are the numbers 2,3,5,7,11, ..,pn,... of set S > Reason: definition of primes > > (3) Let us instead pick the numbers of primes as > the succession of 2,3,5,7,. . , p(n), p(n+2) where > the p(n) and p(n+2) are twin primes > > > (4.0) Suppose twin primes are finite, then 2,3,5, ..,p_n , > p_n+2 is the complete series set > with p_n and p_n+2 the last and largest twin primes Reason: this is > the supposition step > > > (4.1) Set S are the only primes that exist Reason: from step (4.0) > This is the step in which I hesitated in calling > my proof a genuine proof because I pictured larger regular primes > beyond the p_n+2, but that was superfluous > Set S are the only primes that exist between 2,3, . . p_n, p_n+2 Bill, would you evaluate whether I cleared that up? > > (4.2) Form W+1 = (2x3x5x, ..,xp_n x p_n+2) + 1. > And form W-1 = (2x3x5x, ..,xp_n x p_n+2) - 1. > Reason: can always operate and > form a new number > > > (4.3) Divide W+1 and W-1 successively by each prime of > 2,3,5,7,11,..p_n+2 and they all leave a remainder of 1. > Reason: unique prime factorization theorem > > Now here is where my previous proof attempts failed and here is the > patch I wish to apply to stop it from failing. If I apply a patch so > as to eliminate all the regular primes beyond p_n+2 then the proof > works. > And the way I do that is apply a square root to the > W+1 signifying that no primes above p_n+2 will be a factor of W+1 or > W-1 > > (4.4) W+1 and W-1 are necessarily prime. Reason: definition of prime, > step > (1). > > > (4.5) Contradiction Reason: p_n+2 was supposed the largest twin prime > yet we > constructed a new twin primes, W+1 and W-1, larger than p_n+2 > > > (4.6) Reverse supposition step. Reason (4.5) coupled with (4.0) > > > (5) Set of twinprimes are infinite Reason: steps (1) through (4.6) > > XXXXXX > > Now a identical proof procedure works for Quad primes > of p_n and p_n+4, and for the 6th prime pairs of > p_n and p_n+6 > > Now, however there maybe a sticking point as to the application of the > square root so as to keep higher primes of regular primes from > interfering into the proof. > > I will probably have to make piecemeal corrections in the above so do > not let the above be the final word. > Bill, I am hoping you can render a opinion as to whether the square root patch above elminates the pesky regular primes out of the picture? Archimedes Plutonium http://www.iw.net/~a_plutonium/ whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |