From: Patrick on 11 Mar 2010 00:11 Trying to to figure out why my code wont output a plot... any help from willing debuggers out there. Simple code. function running_stride_2 w = input ('Please enter the weight of the runner (lbs): '); % w= weight of the runner a = 9.8; m=((w*0.45359237)/a); disp ('Please enter the shoe of the runner :'); % s = shoe of the runner disp ('1 = Nike'); disp ('2 = Adidas'); disp ('3 = Asics'); disp ('4 = New Balance'); s = input( 'Shoe brand: '); % various shoes have various spring constants and damping coefficients if (s == 1); c = 41.96; k = 41957.30; end; if (s == 2); c = 30.44; k = 23435.61; end; if (s == 3); c = 44.34; k = 29483.51; end; if (s == 4); c = 31.42; k = 26081.56; end; v = input ('Please enter the speed of the runner (0-15m/s):'); % xdot = velocity of the runner if (v >= 0 || v <= 4); x = 2/1000; pheta = (0.261799388:0.01:-0.261799388); end; if (v >= 5 || v <= 8); x = 3.5/1000; pheta = (0.34906585:0.01:-0.34906585); end; if (v >= 9 || v <= 15); x = 5/1000; pheta = (0.436332313:0.01:-0.436332313); end; mu = 0.65; %Horizontal Forces Fh = m*a*sin(pheta)-c*v*sin(pheta)-k*x*sin(pheta)-mu*m*a*cos(pheta) %Vertical Forces Fv = m*a*cos(pheta)-(m*a*cos(pheta)-c*v*cos(pheta)-k*x*cos(pheta)) %Horizontal Force Plots subplot(2,1,1); axis([-4, 4, -1000, 1000]); plot(pheta, Fh) ylabel('Force') xlabel('Stride Progression') %Vertical Force Plots subplot(2,1,2); axis([-4, 4, -1000, 1000]); plot(pheta, Fv) ylabel('Force') xlabel('Stride Progression')
From: Justus Skorps on 11 Mar 2010 00:56 > if (v >= 9 || v <= 15); do you really want the condition in that way? And btw what for speeds like 8.5? > pheta = (0.436332313:0.01:-0.436332313); rtfm how vectors are defined...
From: Patrick on 11 Mar 2010 01:07 Justus Skorps <jussa(a)gmx.de> wrote in message <7525f739-902f-478b-8b8d-621531e26209(a)33g2000yqj.googlegroups.com>... > > if (v >= 9 || v <= 15); > > do you really want the condition in that way? And btw what for speeds > like 8.5? > > > pheta = (0.436332313:0.01:-0.436332313); > > rtfm how vectors are defined... > Thanks for the catch on the speeds. I am not sure what you mean by 'how are the vectors defined?' which ones are you referring to?
From: Justus Skorps on 11 Mar 2010 01:50 On 11 Mrz., 07:07, "Patrick " <pj...(a)drexel.edu> wrote: > I am not sure what you mean by 'how are the vectors defined?' which ones are you referring to? I refering to your definition of pheta...you define the start value, the incremental value and the end value. Take a look on your choices and figure out why that cannnot work...
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