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From: ydbc on 28 Oct 2009 05:52 Hi Please help. I have created a form with a subform. I have a 2 combo boxes in the subform. When I choose an option on the 1st combo box it restricts the choices through an SQL query on the other combo box. However, the 2nd combo box, when restricted will only let me choose the first option. Any ideas? -- ydbc
From: Jeff Boyce on 28 Oct 2009 14:18 What are the queries/SQL statements that 'feed' those comboboxes? Regards Jeff Boyce Microsoft Access MVP -- Disclaimer: This author may have received products and services mentioned in this post. Mention and/or description of a product or service herein does not constitute endorsement thereof. Any code or psuedocode included in this post is offered "as is", with no guarantee as to suitability. You can thank the FTC of the USA for making this disclaimer possible/necessary. "ydbc" <ydbc(a)discussions.microsoft.com> wrote in message news:897EBCFD-7A4C-4E92-A50B-5ABC9D0102D0(a)microsoft.com... > Hi > > Please help. > > I have created a form with a subform. I have a 2 combo boxes in the > subform. > > When I choose an option on the 1st combo box it restricts the choices > through an SQL query on the other combo box. > > However, the 2nd combo box, when restricted will only let me choose the > first option. > > Any ideas? > > > -- > ydbc
From: Anthony Fontana on 28 Oct 2009 15:23 You may want to check out MS KB article 209595 - "How to Synchronize Two Combo Boxes on a Form." That article helped me get started You can also use the Build dialog box to add a reference to the one combo box in a second combo box as part of query criteria. Of course, that requires the combo boxes be used in a particular sequence. "ydbc" wrote: > Hi > > Please help. > > I have created a form with a subform. I have a 2 combo boxes in the subform. > > When I choose an option on the 1st combo box it restricts the choices > through an SQL query on the other combo box. > > However, the 2nd combo box, when restricted will only let me choose the > first option. > > Any ideas? > > > -- > ydbc
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