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From: Matthew Collett on 29 Jun 2010 17:08
In article <073c8b78-95bd-41bf-94b2-c64a86904dd0(a)j8g2000yqd.googlegroups.com>,
Jag <jagnpu(a)gmail.com> wrote:

> I don't understand. Can some one explain the issue here. Thanks
> ------------
> template <typename T>
> static typename list<int>::iterator find_an_element(list<T>& a, const
^^^
Typo here: 'list<int>::iterator' should obviously be 'list<T>::iterator'.

> T& b) {
> typename list<T>::iterator itt = a.begin() ;
> while (itt != a.end()) {
> if (*itt == b) {
> break ;
> }
> itt++ ;
> }
> return itt ;
> }

If T were int* you would get almost, but not quite, the error your title
reports; the return would need exactly the opposite conversion.

Best wishes,
Matthew

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