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From: a boy on 20 May 2010 06:39
In my opinion, the red-blue critical graph (R(n,n)-1 nodes) for
diagonal Ramsey number R(n,n)=r have two self-symmetry below:
1. It exists at least one node that the number of its red edges is
same as blue, equal to (r-2)/2, so r-2 is even;
2. In the critical graph, the number of all red edges is as many as
blue, each equal to (r-2)(r-1)/4, so r-2=4k or r-1=4k.
In a word, diagonal Ramsey number R(n,n) = 4k+2.
R(2,2)=2, R(3,3)=6, R(4,4)=18 follow this form all. It has been known
that R(5,5) is between [43, 49], only 46 has the form 4k+2, so I think
R(5,5)=46

References: http://mathworld.wolfram.com/RamseyNumber.html
http://en.wikipedia.org/wiki/Ramsey's_theorem

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Any reply is welcome!

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