From: Eyal on 11 Mar 2010 13:20 I tried to use lineareq and dfe, with lms and a training sequence, but they only seem to work when the channel filter's coefficients are all positive. I use: eqobj = lineareq(30, lms(0.01), [1+i 1-i -1+j -1-j],4); for i=1:1000 y(i,:)=equalize(eqobj, ComplexSymbols(i,:), CorrectComplexSymbols(i,:)); end where ComplexSymbols is the signal at a sampling rate of symbol_rate*4, and has length 4 times of CorrectComplexSymbols. Additionaly, the signal is OQPSK - the I and the Q are transmitted at a half symbol offset. Am I doing something wrong, or is this the case? They don't correct my actual signal, I suspect that it is for this reason
From: Eyal on 11 Mar 2010 13:32 "Eyal " <eyallzevel(a)gmail.com> wrote in message <hnbc97$qbp$1(a)fred.mathworks.com>... > I tried to use lineareq and dfe, with lms and a training sequence, but they only seem to work when the channel filter's coefficients are all positive. > I use: > eqobj = lineareq(30, lms(0.01), [1+i 1-i -1+j -1-j],4); > for i=1:1000 > y(i,:)=equalize(eqobj, ComplexSymbols(i,:), CorrectComplexSymbols(i,:)); > end > where ComplexSymbols is the signal at a sampling rate of symbol_rate*4, and has length 4 times of CorrectComplexSymbols. > Additionaly, the signal is OQPSK - the I and the Q are transmitted at a half symbol offset. > Am I doing something wrong, or is this the case? They don't correct my actual signal, I suspect that it is for this reason I forgot to mention: the length of ComplexSymbols is 71 (CorectComplexSymbols's is 284) and I do also "eqobj.ResetBeforeFiltering=0" before the loop. also all(sum(abs(ComplexSymbols).^2,2)==1)==1, and CorrectComplexSymbols's values are only of [1+i 1-i -1+j -1-j]
From: Ethem Sozer on 11 Mar 2010 14:15 Hi Eyal, It is hard to comment on what is going on without more information. Can you include a simple script that shows the problem? Especially, the channel coefficients, noise level, Doppler spread etc. Regards, Ethem "Eyal " <eyallzevel(a)gmail.com> wrote in message news:hnbc97$qbp$1(a)fred.mathworks.com... >I tried to use lineareq and dfe, with lms and a training sequence, but they >only seem to work when the channel filter's coefficients are all positive. >I use: > eqobj = lineareq(30, lms(0.01), [1+i 1-i -1+j -1-j],4); > for i=1:1000 > y(i,:)=equalize(eqobj, ComplexSymbols(i,:), > CorrectComplexSymbols(i,:)); > end > where ComplexSymbols is the signal at a sampling rate of symbol_rate*4, > and has length 4 times of CorrectComplexSymbols. > Additionaly, the signal is OQPSK - the I and the Q are transmitted at a > half symbol offset. > Am I doing something wrong, or is this the case? They don't correct my > actual signal, I suspect that it is for this reason
From: Eyal on 12 Mar 2010 15:03 I tried again a simulation with negative coefficients and it worked. probably made a mistake last time. I don't know the real channel's coefficients. can you post me maybe a link to somewhere that explains about this subject? (I don't know what doppler spread is) "Ethem Sozer" <esozer(a)mathworks.com> wrote in message <hnbfgr$scl$1(a)fred.mathworks.com>... > Hi Eyal, > It is hard to comment on what is going on without more information. Can you > include a simple script that shows the problem? Especially, the channel > coefficients, noise level, Doppler spread etc. > Regards, > Ethem > > > "Eyal " <eyallzevel(a)gmail.com> wrote in message > news:hnbc97$qbp$1(a)fred.mathworks.com... > >I tried to use lineareq and dfe, with lms and a training sequence, but they > >only seem to work when the channel filter's coefficients are all positive. > >I use: > > eqobj = lineareq(30, lms(0.01), [1+i 1-i -1+j -1-j],4); > > for i=1:1000 > > y(i,:)=equalize(eqobj, ComplexSymbols(i,:), > > CorrectComplexSymbols(i,:)); > > end > > where ComplexSymbols is the signal at a sampling rate of symbol_rate*4, > > and has length 4 times of CorrectComplexSymbols. > > Additionaly, the signal is OQPSK - the I and the Q are transmitted at a > > half symbol offset. > > Am I doing something wrong, or is this the case? They don't correct my > > actual signal, I suspect that it is for this reason >
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