From: John Ertle Jr. on
In[82]:= J =
367*y + floor (7*(y + floor ((m + 9)/12))/4) + int (275*m/9) + da +
1721013.5

Out[82]= 2.44254*10^6 + 7/4 floor (1966 + (17 floor)/12) + (2200 int)/
9

How do you evaluate the floor s in the output in this example to yield a number for the Julian Date.

From: Murray Eisenberg on
What symbolic system are your trying to use? Built-in objects in
Mathematica have names beginning with upper-case letters; function calls
surround their arguments with square-brackets, not parentheses.

In any case, I don't see any "s" in the output.

The relevant Mathematica function is -- guess what! -- Floor to
calculate the floor of something. Of course you cannot expect it to do
an actual evaluation of the Floor of something unless all the variables
inside the argument already have actual numeric values.

On 4/9/2010 3:34 AM, John Ertle Jr. wrote:
> In[82]:= J =
> 367*y + floor (7*(y + floor ((m + 9)/12))/4) + int (275*m/9) + da +
> 1721013.5
>
> Out[82]= 2.44254*10^6 + 7/4 floor (1966 + (17 floor)/12) + (2200 int)/
> 9
>
> How do you evaluate the floor s in the output in this example to yield a number for the Julian Date.
>

--
Murray Eisenberg murray(a)math.umass.edu
Mathematics & Statistics Dept.
Lederle Graduate Research Tower phone 413 549-1020 (H)
University of Massachusetts 413 545-2859 (W)
710 North Pleasant Street fax 413 545-1801
Amherst, MA 01003-9305

From: Bill Rowe on
On 4/9/10 at 3:34 AM, ertlejack(a)sbcglobal.net (John Ertle Jr.) wrote:

>In[82]:= J = 367*y + floor (7*(y + floor ((m + 9)/12))/4) + int
>(275*m/9) + da +
>1721013.5

>Out[82]= 2.44254*10^6 + 7/4 floor (1966 + (17 floor)/12) + (2200
>int)/
>9

>How do you evaluate the floor s in the output in this example to
>yield a number for the Julian Date.

You will have a lot more success if you use valid Mathematica
syntax and spend some time reading the documentation. All
built-in Mathematica functions start with an upper case letter
and function arguments should be surrounded by square brackets,
"[" and "]" not "(" and ")". That is

In[34]:= 367*y + Floor[7*(y + Floor [(m + 9)/12])/4] +
IntegerPart [275*m/9] + da + 1721013.5 /. {y -> 2010, m -> 4,
da -> 15}

Out[34]= 2.46234*10^6


From: John Ertle Jr. on
I figured out that if you try to manipulate the data the floor will no reevaluate. You just have to make a new notebook!