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From: us on 6 Apr 2010 23:48 Mike > Sorry i've made mistakes. It should be the second-to and third-to > last. by now you wasted several lengthy replies - and CSSMers time - for just being sorry for having made yet another mistake... why don't you THINK for a while, then get your act together, and then come back with a - brief - precise - concise question(?)... us
From: Nathan on 6 Apr 2010 23:55 On Apr 6, 8:48 pm, "us " <u...(a)neurol.unizh.ch> wrote: > Mike > > > Sorry i've made mistakes. It should be the second-to and third-to > > last. > > by now you wasted several lengthy replies - and CSSMers time - for just being sorry for having made yet another mistake... > > why don't you THINK for a while, then get your act together, and then come back with a > - brief > - precise > - concise > question(?)... > > us He did ask for what he wanted, but I have some further questions for clarification. " I want to find images are within some T dates. Let's say T=7 for second column. So the output should be: group1=[ id10 2; id2 5; id3 3] group2=[ id7 90; id20 91;] Since the numbers in these two groups are within T. Mike" The given numbers are the solution because they fall within a range of 7 digits. 2 3 5 is a max range of 5-2 = 3. 90 91 is a max range of 91 - 90 = 1. These values are less than 7, so they work. None of the numbers are within 7 digits of 66, so that is not included in the answer. My question for clarification is what if the numbers 1:10 are part of the set. Is the premise that one number must be within 7 digits of another, or is it that a series of numbers must be within 7 digits of each other? -Nathan
From: Mike on 7 Apr 2010 00:01 On Apr 7, 11:48 am, "us " <u...(a)neurol.unizh.ch> wrote: > Mike > > > Sorry i've made mistakes. It should be the second-to and third-to > > last. > > by now you wasted several lengthy replies - and CSSMers time - for just being sorry for having made yet another mistake... > > why don't you THINK for a while, then get your act together, and then come back with a > - brief > - precise > - concise > question(?)... > > us Sorry again. I'll THINK it very carefully. Mike
From: Mike on 7 Apr 2010 00:08 On Apr 7, 11:55 am, Nathan <ngrec...(a)gmail.com> wrote: > On Apr 6, 8:48 pm, "us " <u...(a)neurol.unizh.ch> wrote: > > > Mike > > > > Sorry i've made mistakes. It should be the second-to and third-to > > > last. > > > by now you wasted several lengthy replies - and CSSMers time - for just being sorry for having made yet another mistake... > > > why don't you THINK for a while, then get your act together, and then come back with a > > - brief > > - precise > > - concise > > question(?)... > > > us > > He did ask for what he wanted, but I have some further questions for > clarification. > > " I want to find images > are within some T dates. Let's say T=7 for second column. > So the output should be: > > group1=[ id10 2; > id2 5; > id3 3] > > group2=[ id7 90; > id20 91;] > Since the numbers in these two groups are within T. > Mike" > > The given numbers are the solution because they fall within a range of > 7 digits. 2 3 5 is a max range of 5-2 = 3. > 90 91 is a max range of 91 - 90 = 1. These values are less than 7, so > they work. > > None of the numbers are within 7 digits of 66, so that is not included > in the answer. Yes. > > My question for clarification is what if the numbers 1:10 are part of > the set. > Is the premise that one number must be within 7 digits of another, or > is it that a series of numbers must be within 7 digits of each other? I'd like to have the series of numbers being within 7 of eacher other. So if the numbers are 1:10, then the results need to show 1:7, 2:8, 3:9 and 4:10. These four series of data are all answers. But the original data are not sorted. Mike > > -Nathan
From: Mike on 8 Apr 2010 02:06 On Apr 7, 12:08 pm, Mike <sulfate...(a)gmail.com> wrote: > On Apr 7, 11:55 am, Nathan <ngrec...(a)gmail.com> wrote: > > > > > On Apr 6, 8:48 pm, "us " <u...(a)neurol.unizh.ch> wrote: > > > > Mike > > > > > Sorry i've made mistakes. It should be the second-to and third-to > > > > last. > > > > by now you wasted several lengthy replies - and CSSMers time - for just being sorry for having made yet another mistake... > > > > why don't you THINK for a while, then get your act together, and then come back with a > > > - brief > > > - precise > > > - concise > > > question(?)... > > > > us > > > He did ask for what he wanted, but I have some further questions for > > clarification. > > > " I want to find images > > are within some T dates. Let's say T=7 for second column. > > So the output should be: > > > group1=[ id10 2; > > id2 5; > > id3 3] > > > group2=[ id7 90; > > id20 91;] > > Since the numbers in these two groups are within T. > > Mike" > > > The given numbers are the solution because they fall within a range of > > 7 digits. 2 3 5 is a max range of 5-2 = 3. > > 90 91 is a max range of 91 - 90 = 1. These values are less than 7, so > > they work. > > > None of the numbers are within 7 digits of 66, so that is not included > > in the answer. > Yes. > > > My question for clarification is what if the numbers 1:10 are part of > > the set. > > Is the premise that one number must be within 7 digits of another, or > > is it that a series of numbers must be within 7 digits of each other? > > I'd like to have the series of numbers being within 7 of eacher other. > So if the numbers are 1:10, then the results need to show > 1:7, 2:8, 3:9 and 4:10. These four series of data are all answers. > But the original data are not sorted. > Mike > > > > > > > -Nathan- Hide quoted text - > > - Show quoted text -- Hide quoted text - > > - Show quoted text - Just repost it.
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