finding a predefined row in a matrix and delete it..!
in [Matlab]
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From: us on 12 Jun 2010 08:40 "Cyberbrain " <afatnassi(a)hotmail.com> wrote in message <huvurt$44l$1(a)fred.mathworks.com>... > "Wayne King" <wmkingty(a)gmail.com> wrote in message <huvu5d$kfd$1(a)fred.mathworks.com>... > > "Fatnassi " <afatnassi(a)hotmail.com> wrote in message <huvsgt$9l4$1(a)fred.mathworks.com>... > > > Hi everybody, > > > I´m looking for a compact way to localize a row in a matrix > > > deleting that row and reshaping the matrix..! to a new one without the found row..! > > > The problem is has to be compact cause it will be a part of a very long script with GUI and i have to spare some ram ...so solution with loops ...will not solve my problem.. > > > > > > Thunks..! > > > > Hi Fatnassi, The best way depends on the entries in the matrix. For example, find() may work well in some instances and not in others. I think you should give us a little more detail on what characteristics the particular row has, or rows have, that you wish to delete. > > > > Wayne > > > Thunks for your answer...! > I just need to delete a row from a matrix...! so this is what i meant.. : > > x=[l c] > M=[1 2;5 7;46 44;45 35] > x is of course a variable vector and i want to find out if that row is defined > in my matrix M and if yes than delete it and reshape the matrix M..! > > Thunks! be more clear... what are L/C in your X(?)... show an example, which makes sense... us
From: Cyberbrain on 12 Jun 2010 08:48 "us " <us(a)neurol.unizh.ch> wrote in message <huvv7n$qcd$1(a)fred.mathworks.com>... > "Cyberbrain " <afatnassi(a)hotmail.com> wrote in message <huvurt$44l$1(a)fred.mathworks.com>... > > "Wayne King" <wmkingty(a)gmail.com> wrote in message <huvu5d$kfd$1(a)fred.mathworks.com>... > > > "Fatnassi " <afatnassi(a)hotmail.com> wrote in message <huvsgt$9l4$1(a)fred.mathworks.com>... > > > > Hi everybody, > > > > I´m looking for a compact way to localize a row in a matrix > > > > deleting that row and reshaping the matrix..! to a new one without the found row..! > > > > The problem is has to be compact cause it will be a part of a very long script with GUI and i have to spare some ram ...so solution with loops ...will not solve my problem.. > > > > > > > > Thunks..! > > > > > > Hi Fatnassi, The best way depends on the entries in the matrix. For example, find() may work well in some instances and not in others. I think you should give us a little more detail on what characteristics the particular row has, or rows have, that you wish to delete. > > > > > > Wayne > > > > > > Thunks for your answer...! > > I just need to delete a row from a matrix...! so this is what i meant.. : > > > > x=[l c] > > M=[1 2;5 7;46 44;45 35] > > x is of course a variable vector and i want to find out if that row is defined > > in my matrix M and if yes than delete it and reshape the matrix M..! > > > > Thunks! > > be more clear... > what are L/C in your X(?)... > show an example, which makes sense... > > us ok..! for example for the case that x=[46 44] M=[1 2;5 7;46 44;45 35] in this case i want to get the new M=[1 2;5 7;45 35] and for the case that x=[46 7] (notice that the two elements are in my matrix but i need to find out if the whole row x is in the matrix or not..!) M stills the same..! thunks!
From: us on 12 Jun 2010 08:56 "Cyberbrain " <afatnassi(a)hotmail.com> wrote in message <huvvm5$o2a$1(a)fred.mathworks.com>... > "us " <us(a)neurol.unizh.ch> wrote in message <huvv7n$qcd$1(a)fred.mathworks.com>... > > "Cyberbrain " <afatnassi(a)hotmail.com> wrote in message <huvurt$44l$1(a)fred.mathworks.com>... > > > "Wayne King" <wmkingty(a)gmail.com> wrote in message <huvu5d$kfd$1(a)fred.mathworks.com>... > > > > "Fatnassi " <afatnassi(a)hotmail.com> wrote in message <huvsgt$9l4$1(a)fred.mathworks.com>... > > > > > Hi everybody, > > > > > I´m looking for a compact way to localize a row in a matrix > > > > > deleting that row and reshaping the matrix..! to a new one without the found row..! > > > > > The problem is has to be compact cause it will be a part of a very long script with GUI and i have to spare some ram ...so solution with loops ...will not solve my problem.. > > > > > > > > > > Thunks..! > > > > > > > > Hi Fatnassi, The best way depends on the entries in the matrix. For example, find() may work well in some instances and not in others. I think you should give us a little more detail on what characteristics the particular row has, or rows have, that you wish to delete. > > > > > > > > Wayne > > > > > > > > > Thunks for your answer...! > > > I just need to delete a row from a matrix...! so this is what i meant.. : > > > > > > x=[l c] > > > M=[1 2;5 7;46 44;45 35] > > > x is of course a variable vector and i want to find out if that row is defined > > > in my matrix M and if yes than delete it and reshape the matrix M..! > > > > > > Thunks! > > > > be more clear... > > what are L/C in your X(?)... > > show an example, which makes sense... > > > > us > > > ok..! for example for the case that > x=[46 44] > M=[1 2;5 7;46 44;45 35] > in this case i want to get the new M=[1 2;5 7;45 35] > > and for the case that x=[46 7] (notice that the two elements are in my matrix > but i need to find out if the whole row x is in the matrix or not..!) > M stills the same..! > thunks! one of the many solutions m=[ 1 44 2 3 44 45 45 44 4 5 ]; x=[44,45]; ix=ismember(m,x,'rows'),2; m(ix,:)=[] %{ % ans = 1 44 2 3 45 44 % <- note: same numbers but diff order... 4 5 %} us
From: Cyberbrain on 12 Jun 2010 09:03 Dude that´s exactly the compact solution that i´m looking for ...! Thunks...!
From: Wayne King on 12 Jun 2010 09:04 "Cyberbrain " <afatnassi(a)hotmail.com> wrote in message <huvvm5$o2a$1(a)fred.mathworks.com>... > "us " <us(a)neurol.unizh.ch> wrote in message <huvv7n$qcd$1(a)fred.mathworks.com>... > > "Cyberbrain " <afatnassi(a)hotmail.com> wrote in message <huvurt$44l$1(a)fred.mathworks.com>... > > > "Wayne King" <wmkingty(a)gmail.com> wrote in message <huvu5d$kfd$1(a)fred.mathworks.com>... > > > > "Fatnassi " <afatnassi(a)hotmail.com> wrote in message <huvsgt$9l4$1(a)fred.mathworks.com>... > > > > > Hi everybody, > > > > > I´m looking for a compact way to localize a row in a matrix > > > > > deleting that row and reshaping the matrix..! to a new one without the found row..! > > > > > The problem is has to be compact cause it will be a part of a very long script with GUI and i have to spare some ram ...so solution with loops ...will not solve my problem.. > > > > > > > > > > Thunks..! > > > > > > > > Hi Fatnassi, The best way depends on the entries in the matrix. For example, find() may work well in some instances and not in others. I think you should give us a little more detail on what characteristics the particular row has, or rows have, that you wish to delete. > > > > > > > > Wayne > > > > > > > > > Thunks for your answer...! > > > I just need to delete a row from a matrix...! so this is what i meant.. : > > > > > > x=[l c] > > > M=[1 2;5 7;46 44;45 35] > > > x is of course a variable vector and i want to find out if that row is defined > > > in my matrix M and if yes than delete it and reshape the matrix M..! > > > > > > Thunks! > > > > be more clear... > > what are L/C in your X(?)... > > show an example, which makes sense... > > > > us > > > ok..! for example for the case that > x=[46 44] > M=[1 2;5 7;46 44;45 35] > in this case i want to get the new M=[1 2;5 7;45 35] > > and for the case that x=[46 7] (notice that the two elements are in my matrix > but i need to find out if the whole row x is in the matrix or not..!) > M stills the same..! > thunks! Hi, I think in your case: [C,IA,IB] = intersect(M,x,'rows'); M(IA,:) = []; would work. Wayne
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