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From: Namo on 23 Mar 2010 05:15
Before I start , I will define some variables
a is the initial value
b is the final value
i is the increment
n is number of vales in the vector

if we have a,b and i
v=[a:i:b]

if we have a,b and n
v=linspace(a,b,n)

if we have a , i and n , I use the equation n=(b-a)/i + 1
b = i*(n-1) + a

then use any of the previous one

Is there direct function if we have a,i,n?
From: Matt Fig on 23 Mar 2010 08:49
These can all be gotten with the colon operator, barring fp problems of course.

a:inc:b % No number of elements
a:(b-a)/(n-1):b % No increment
a:inc:(a+inc*(n-1)) % No endpoint
(b-inc*(n-1)):inc:b % No beginning point
From: Namo on 15 Apr 2010 11:47
"Matt Fig" <spamanon(a)yahoo.com> wrote in message <hoadci$m9r$1(a)fred.mathworks.com>...
> These can all be gotten with the colon operator, barring fp problems of course.
>
> a:inc:b % No number of elements
> a:(b-a)/(n-1):b % No increment
> a:inc:(a+inc*(n-1)) % No endpoint
> (b-inc*(n-1)):inc:b % No beginning point

I see so there is no special function. we just need to rearrange the equation
b = i*(n-1) + a
for our need
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