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From: Andy on 13 Aug 2010 14:48
But that's just silly. You've used eval in a loop to create the separate variables, only to use eval again to put them together. But you have them together in the 1400x5 array a to start out with! You could just use:

M = <1x7000 double>

b = 5;
c = 1;
a = zeros(1400,5);
for k = 1:1400
a(k,:) = M(idx(1,c:b));
b = b+5;
c = c+5;
d(k,:) = mean(a(k,:));
end

Now wherever you had previously used a_n, you should instead use a(n,:). And when you want all of the vectors together, you already have the array a.

As a sidenote, I think the entire loop above can be replaced with (I'm not at MATLAB right now, so you may need to fiddle with this):

M = <1x7000 double>
a = reshape(M,[1400 5]);
d = mean(a);
From: Dave400 on 13 Aug 2010 19:33
"Andy " <myfakeemailaddress(a)gmail.com> wrote in message <i4441k$ese$1(a)fred.mathworks.com>...
> But that's just silly. You've used eval in a loop to create the separate variables, only to use eval again to put them together. But you have them together in the 1400x5 array a to start out with! You could just use:
>
> M = <1x7000 double>
>
> b = 5;
> c = 1;
> a = zeros(1400,5);
> for k = 1:1400
> a(k,:) = M(idx(1,c:b));
> b = b+5;
> c = c+5;
> d(k,:) = mean(a(k,:));
> end
>
> Now wherever you had previously used a_n, you should instead use a(n,:). And when you want all of the vectors together, you already have the array a.
>
> As a sidenote, I think the entire loop above can be replaced with (I'm not at MATLAB right now, so you may need to fiddle with this):
>
> M = <1x7000 double>
> a = reshape(M,[1400 5]);
> d = mean(a);

Thanks to everyone for there help.

I will looking to each of the methods suggested and will plan to be more efficicent in the furture.

Cheers

DR
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