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From: Sneaky Wombat on 25 Jun 2010 16:20
Why is python turning \x0a into a \n ?

In [120]: h='\x0a\xa8\x19\x0b'

In [121]: h
Out[121]: '\n\xa8\x19\x0b'


I don't want this to happen, can I prevent it?

From: Emile van Sebille on 25 Jun 2010 16:35
On 6/25/2010 1:20 PM Sneaky Wombat said...
> Why is python turning \x0a into a \n ?
>
> In [120]: h='\x0a\xa8\x19\x0b'
>
> In [121]: h
> Out[121]: '\n\xa8\x19\x0b'
>
>
> I don't want this to happen, can I prevent it?
>


It's not happening. What you're seeing is the representation of the
four bytes, and \x0a _is_ \n and python displays the common form to
assist interpretation.

What you can do is write a display function to suit your needs if it
makes a difference.

\x48\x54\x48\x2c

Emile

From: Ethan Furman on 25 Jun 2010 16:53
Sneaky Wombat wrote:
> Why is python turning \x0a into a \n ?
>
> In [120]: h='\x0a\xa8\x19\x0b'
>
> In [121]: h
> Out[121]: '\n\xa8\x19\x0b'
>
>
> I don't want this to happen, can I prevent it?

'\x0a' == '\n'

From: Dave Angel on 25 Jun 2010 17:55
Sneaky Wombat wrote:
> Why is python turning \x0a into a \n ?
>
> In [120]: h='\x0a\xa8\x19\x0b'
>
> In [121]: h
> Out[121]: '\n\xa8\x19\x0b'
>
>
> I don't want this to happen, can I prevent it?
>
>
>
You don't say what you do want. Currently, you have a literal that
describes four characters. Were you trying for 7 ? If so, try escaping
the first backslash.
h2 = '\\x0a\xa8\x19\x0b'

On the other hand, maybe you're really trying for four, and think that
the first one is different than you intended. It's not. You have to
realize that the interactive interpreter is using repr() on that string,
and a string representation chooses the mnemonic versions over the hex
version. There are frequently several ways to represent a given
character, and once the character has been stored, repr() will use its
own judgment on how to show it.

For a simpler example,
b = '\x41\x42c'
b
will display ABc

'x41' is just another way of saying 'A'. And '\0a' is just another
way of saying '\n' or newline.

DaveA

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