how can you increase variables in matlab?
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From: James Tursa on 11 Aug 2010 04:02 "Christopher " <christopher.serojano(a)veco.com.ph> wrote in message <i3tii1$nbd$1(a)fred.mathworks.com>... > > h = [sum(a(1:4,5)).*b(1,1).*0.25 sum(a(5:8,5)).*b(2,1).*0.25 sum(a(9:12,5)).*b(3,1).*0.25 sum(a(13:16,5)).*b(4,1).*0.25 sum(a(17:20,5)).*b(5,1).*0.25 sum(a(21:24,5)).*b(6,1).*0.25... > sum(a(25:28,5)).*b(7,1).*0.25 sum(a(29:32,5)).*b(8,1).*0.25 sum(a(33:36,5)).*b(9,1).*0.25 sum(a(37:40,5)).*b(10,1).*0.25 sum(a(41:44,5)).*b(11,1).*0.25 sum(a(45:48,5)).*b(12,1).*0.25... > sum(a(49:52,5)).*b(13,1).*0.25 sum(a(53:56,5)).*b(14,1).*0.25 sum(a(57:60,5)).*b(15,1).*0.25 sum(a(61:64,5)).*b(16,1).*0.25 sum(a(65:68,5)).*b(17,1).*0.25 sum(a(69:72,5)).*b(18,1).*0.25... > sum(a(73:76,5)).*b(19,1).*0.25 sum(a(77:80,5)).*b(20,1).*0.25 sum(a(81:84,5)).*b(21,1).*0.25 sum(a(85:88,5)).*b(22,1).*0.25 sum(a(89:92,5)).*b(23,1).*0.25 sum(a(93:96,5)).*b(24,1).*0.25]'; You might consider vectorizing your code. For example, the entire h expression above can be replaced with: h = (sum(bsxfun(@times,reshape(a(:,5),4,24),reshape(b(:,1),1,24)))*0.25).' > f = sum(e) + x(1)*c(5,1)*0.25 + x(2)*c(5,1)*0.25 +x(3)*c(5,1)*0.25+x(4)*c(5,1)*0.25+x(5)*c(5,1)*0.25+x(6)*c(5,1)*0.25+x(7)*c(5,1)*0.25+x(8)*c(5,1)*0.25+x(9)*c(5,1)*0.25+x(10)*c(5,1)*0.25+x(11)*c(5,1)*0.25+x(12)*c(5,1)*0.25+x(13)*c(5,1)*0.25+x(14)*c(5,1)*0.25+x(15)*c(5,1)*0.25+x(16)*c(5,1)*0.25+... > x(17)*c(5,1)*0.25 And why do you have all those multiplies? Why not factor the c(5,1)*0.25 out of the expression and multiply it by the sum of x(1) through x(17)? James Tursa
From: Ross W on 11 Aug 2010 04:05 "Christopher " <christopher.serojano(a)veco.com.ph> wrote in message <i3tii1$nbd$1(a)fred.mathworks.com>... > "James Tursa" <aclassyguy_with_a_k_not_a_c(a)hotmail.com> wrote in message <i3tiah$bh2$1(a)fred.mathworks.com>... > > "Christopher " <christopher.serojano(a)veco.com.ph> wrote in message <i3thee$btv$1(a)fred.mathworks.com>... > > > Hi, > > > > > > I am trying to use a lot of variables for my function but the optimization toolbox states that variable out of bounds because numel(x) = 2 and I can only use two variables say x(1) and x(2). . how can I increase the number of variables say using x(3),x(4),x(5),x(6)... etc.. . > > > > > > Can Anyone help me. . pls > > > > MATLAB can hold roughly 65000 variables, so I doubt you are running into that limit. We can't possibly help you unless you provide more details, and ideally some code for us to look at. > > > > James Tursa > > thank you for your reply this is my code. . > > function f = objfun(x) > a = xlsread('Optimization','weekday','c8:h103'); %demand CEDC - NPC > b = xlsread('Optimization','weekday','l8:m31'); % NPC rates > c = xlsread('Optimization','weekday','q7:q12'); % other rates > d = xlsread('Optimization','weekday','q13:q14');% Cemex and CPPC capacity fee > e = a(:,2).*0.25.*c(4,1); %Cost for CEDC per 15 min > i = 0.25.*c(5,1); %Cost for TPC per 15 min > g = 0.25.*c(1,1); % Cost for CPPC per 15 min > %Cost of NPC for every one hour > h = [sum(a(1:4,5)).*b(1,1).*0.25 sum(a(5:8,5)).*b(2,1).*0.25 sum(a(9:12,5)).*b(3,1).*0.25 sum(a(13:16,5)).*b(4,1).*0.25 sum(a(17:20,5)).*b(5,1).*0.25 sum(a(21:24,5)).*b(6,1).*0.25... > sum(a(25:28,5)).*b(7,1).*0.25 sum(a(29:32,5)).*b(8,1).*0.25 sum(a(33:36,5)).*b(9,1).*0.25 sum(a(37:40,5)).*b(10,1).*0.25 sum(a(41:44,5)).*b(11,1).*0.25 sum(a(45:48,5)).*b(12,1).*0.25... > sum(a(49:52,5)).*b(13,1).*0.25 sum(a(53:56,5)).*b(14,1).*0.25 sum(a(57:60,5)).*b(15,1).*0.25 sum(a(61:64,5)).*b(16,1).*0.25 sum(a(65:68,5)).*b(17,1).*0.25 sum(a(69:72,5)).*b(18,1).*0.25... > sum(a(73:76,5)).*b(19,1).*0.25 sum(a(77:80,5)).*b(20,1).*0.25 sum(a(81:84,5)).*b(21,1).*0.25 sum(a(85:88,5)).*b(22,1).*0.25 sum(a(89:92,5)).*b(23,1).*0.25 sum(a(93:96,5)).*b(24,1).*0.25]'; > > f = sum(e) + x(1)*c(5,1)*0.25 + x(2)*c(5,1)*0.25 +x(3)*c(5,1)*0.25+x(4)*c(5,1)*0.25+x(5)*c(5,1)*0.25+x(6)*c(5,1)*0.25+x(7)*c(5,1)*0.25+x(8)*c(5,1)*0.25+x(9)*c(5,1)*0.25+x(10)*c(5,1)*0.25+x(11)*c(5,1)*0.25+x(12)*c(5,1)*0.25+x(13)*c(5,1)*0.25+x(14)*c(5,1)*0.25+x(15)*c(5,1)*0.25+x(16)*c(5,1)*0.25+... > x(17)*c(5,1)*0.25 > > its not yet finished. . but i tried it in the optimtool. . then an error occurs. . index out of bounds then numel(x) = 2 hi what is the x that you pass into the function? it needs to be a vector with at least 17 elements. is it just a scalar? how are you calling the function? ross
From: Christopher on 11 Aug 2010 04:12 "James Tursa" <aclassyguy_with_a_k_not_a_c(a)hotmail.com> wrote in message <i3tldu$skn$1(a)fred.mathworks.com>... > "Christopher " <christopher.serojano(a)veco.com.ph> wrote in message <i3tii1$nbd$1(a)fred.mathworks.com>... > > > > h = [sum(a(1:4,5)).*b(1,1).*0.25 sum(a(5:8,5)).*b(2,1).*0.25 sum(a(9:12,5)).*b(3,1).*0.25 sum(a(13:16,5)).*b(4,1).*0.25 sum(a(17:20,5)).*b(5,1).*0.25 sum(a(21:24,5)).*b(6,1).*0.25... > > sum(a(25:28,5)).*b(7,1).*0.25 sum(a(29:32,5)).*b(8,1).*0.25 sum(a(33:36,5)).*b(9,1).*0.25 sum(a(37:40,5)).*b(10,1).*0.25 sum(a(41:44,5)).*b(11,1).*0.25 sum(a(45:48,5)).*b(12,1).*0.25... > > sum(a(49:52,5)).*b(13,1).*0.25 sum(a(53:56,5)).*b(14,1).*0.25 sum(a(57:60,5)).*b(15,1).*0.25 sum(a(61:64,5)).*b(16,1).*0.25 sum(a(65:68,5)).*b(17,1).*0.25 sum(a(69:72,5)).*b(18,1).*0.25... > > sum(a(73:76,5)).*b(19,1).*0.25 sum(a(77:80,5)).*b(20,1).*0.25 sum(a(81:84,5)).*b(21,1).*0.25 sum(a(85:88,5)).*b(22,1).*0.25 sum(a(89:92,5)).*b(23,1).*0.25 sum(a(93:96,5)).*b(24,1).*0.25]'; > > You might consider vectorizing your code. For example, the entire h expression above can be replaced with: > > h = (sum(bsxfun(@times,reshape(a(:,5),4,24),reshape(b(:,1),1,24)))*0.25).' > > > f = sum(e) + x(1)*c(5,1)*0.25 + x(2)*c(5,1)*0.25 +x(3)*c(5,1)*0.25+x(4)*c(5,1)*0.25+x(5)*c(5,1)*0.25+x(6)*c(5,1)*0.25+x(7)*c(5,1)*0.25+x(8)*c(5,1)*0.25+x(9)*c(5,1)*0.25+x(10)*c(5,1)*0.25+x(11)*c(5,1)*0.25+x(12)*c(5,1)*0.25+x(13)*c(5,1)*0.25+x(14)*c(5,1)*0.25+x(15)*c(5,1)*0.25+x(16)*c(5,1)*0.25+... > > x(17)*c(5,1)*0.25 > > And why do you have all those multiplies? Why not factor the c(5,1)*0.25 out of the expression and multiply it by the sum of x(1) through x(17)? > > James Tursa I tried it and It has no effect with the optimtool.. the same error occured. . index out of bounds then numel(x)=2
From: Christopher on 11 Aug 2010 04:14 "Ross W" <rosswoodskiwi(a)hotmail.com> wrote in message <i3tlji$b0l$1(a)fred.mathworks.com>... > "Christopher " <christopher.serojano(a)veco.com.ph> wrote in message <i3tii1$nbd$1(a)fred.mathworks.com>... > > "James Tursa" <aclassyguy_with_a_k_not_a_c(a)hotmail.com> wrote in message <i3tiah$bh2$1(a)fred.mathworks.com>... > > > "Christopher " <christopher.serojano(a)veco.com.ph> wrote in message <i3thee$btv$1(a)fred.mathworks.com>... > > > > Hi, > > > > > > > > I am trying to use a lot of variables for my function but the optimization toolbox states that variable out of bounds because numel(x) = 2 and I can only use two variables say x(1) and x(2). . how can I increase the number of variables say using x(3),x(4),x(5),x(6)... etc.. . > > > > > > > > Can Anyone help me. . pls > > > > > > MATLAB can hold roughly 65000 variables, so I doubt you are running into that limit. We can't possibly help you unless you provide more details, and ideally some code for us to look at. > > > > > > James Tursa > > > > thank you for your reply this is my code. . > > > > function f = objfun(x) > > a = xlsread('Optimization','weekday','c8:h103'); %demand CEDC - NPC > > b = xlsread('Optimization','weekday','l8:m31'); % NPC rates > > c = xlsread('Optimization','weekday','q7:q12'); % other rates > > d = xlsread('Optimization','weekday','q13:q14');% Cemex and CPPC capacity fee > > e = a(:,2).*0.25.*c(4,1); %Cost for CEDC per 15 min > > i = 0.25.*c(5,1); %Cost for TPC per 15 min > > g = 0.25.*c(1,1); % Cost for CPPC per 15 min > > %Cost of NPC for every one hour > > h = [sum(a(1:4,5)).*b(1,1).*0.25 sum(a(5:8,5)).*b(2,1).*0.25 sum(a(9:12,5)).*b(3,1).*0.25 sum(a(13:16,5)).*b(4,1).*0.25 sum(a(17:20,5)).*b(5,1).*0.25 sum(a(21:24,5)).*b(6,1).*0.25... > > sum(a(25:28,5)).*b(7,1).*0.25 sum(a(29:32,5)).*b(8,1).*0.25 sum(a(33:36,5)).*b(9,1).*0.25 sum(a(37:40,5)).*b(10,1).*0.25 sum(a(41:44,5)).*b(11,1).*0.25 sum(a(45:48,5)).*b(12,1).*0.25... > > sum(a(49:52,5)).*b(13,1).*0.25 sum(a(53:56,5)).*b(14,1).*0.25 sum(a(57:60,5)).*b(15,1).*0.25 sum(a(61:64,5)).*b(16,1).*0.25 sum(a(65:68,5)).*b(17,1).*0.25 sum(a(69:72,5)).*b(18,1).*0.25... > > sum(a(73:76,5)).*b(19,1).*0.25 sum(a(77:80,5)).*b(20,1).*0.25 sum(a(81:84,5)).*b(21,1).*0.25 sum(a(85:88,5)).*b(22,1).*0.25 sum(a(89:92,5)).*b(23,1).*0.25 sum(a(93:96,5)).*b(24,1).*0.25]'; > > > > f = sum(e) + x(1)*c(5,1)*0.25 + x(2)*c(5,1)*0.25 +x(3)*c(5,1)*0.25+x(4)*c(5,1)*0.25+x(5)*c(5,1)*0.25+x(6)*c(5,1)*0.25+x(7)*c(5,1)*0.25+x(8)*c(5,1)*0.25+x(9)*c(5,1)*0.25+x(10)*c(5,1)*0.25+x(11)*c(5,1)*0.25+x(12)*c(5,1)*0.25+x(13)*c(5,1)*0.25+x(14)*c(5,1)*0.25+x(15)*c(5,1)*0.25+x(16)*c(5,1)*0.25+... > > x(17)*c(5,1)*0.25 > > > > its not yet finished. . but i tried it in the optimtool. . then an error occurs. . index out of bounds then numel(x) = 2 > > hi > > what is the x that you pass into the function? it needs to be a vector with at least 17 elements. is it just a scalar? > > how are you calling the function? > > ross yes x is a scalar.. but it is a variable in which i need to be evaluated to minimize the function. . how can I create a vector with seventeen variables? Is that possible?
From: us on 11 Aug 2010 05:32
"Christopher " > yes x is a scalar.. but it is a variable in which i need to be evaluated to minimize the function. . how can I create a vector with seventeen variables? Is that possible? of course... one of the solutions - for three vars for sake of brevity... v1=1*pi; v2=2*pi; v3=3*pi; va=[v1,v2,v3]; us |