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From: Chip Eastham on 13 May 2010 14:41
On May 13, 2:29 pm, Patrick Coilland <pcoill...(a)pcc.fr> wrote:
> Ray Vickson a écrit :
>
> > On May 13, 9:42 am, Patrick Coilland <pcoill...(a)pcc.fr> wrote:
> >> andrews a écrit :
>
> >>> Hi,
> >>> Is there somebody who can give the solution for the integral of :
> >>> 1/ln(x^x) where ln is the natural logaritme?
> >>> Thanks for a response
> >> ln(ln(x))
>
> > Whys did you give him the answer? Would it not be better to just
> > supply a hint and let the OP work it out for himself?
>
> > R.G. Vickson
>
> He asked for a solution ("Is there somebody who can give the
> solution...") and not a hint.
> Hence my answer.
> Sorry.

If we want to be literal minded, he asked if
someone existed who could give the solution.
The answer, obviously, is yes...

regards, chip
From: andrews on 13 May 2010 15:00
Ray and Patrich, thanks you both and you are both right.
I needed the solution and the answer.
Thanks again
From: Ray Vickson on 13 May 2010 22:01
On May 13, 11:29 am, Patrick Coilland <pcoill...(a)pcc.fr> wrote:
> Ray Vickson a écrit :
>
> > On May 13, 9:42 am, Patrick Coilland <pcoill...(a)pcc.fr> wrote:
> >> andrews a écrit :
>
> >>> Hi,
> >>> Is there somebody who can give the solution for the integral of :
> >>> 1/ln(x^x) where ln is the natural logaritme?
> >>> Thanks for a response
> >> ln(ln(x))
>
> > Whys did you give him the answer? Would it not be better to just
> > supply a hint and let the OP work it out for himself?
>
> > R.G. Vickson
>
> He asked for a solution ("Is there somebody who can give the
> solution...") and not a hint.
> Hence my answer.
> Sorry.

OK, but I am thinking like a (former) instructor. If the OP happens to
be a student, and the question is part of an assignment worth some
course marks, then his request _might_ be re-worded as: "could
somebody please do my homework for me?" I'm not saying that is the
case---just that it _might_ be.

R.G. Vickson
From: Patrick Coilland on 14 May 2010 03:13
Chip Eastham a �crit :
>
> If we want to be literal minded, he asked if
> someone existed who could give the solution.
> The answer, obviously, is yes...
>

:)
From: andrews on 14 May 2010 09:53
I am not a student, thus it is not for a homework.
With the answers I could find the solution.
It is based on int(df/f) = lnf where f is any function
Thanks for this
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