From: Mark Schelbergen on 20 May 2010 09:09 I use the equation below: M=r x F (all vectors) The moment; M and the arm; r are known, is there a way to calculate the force; F? Does matlab has a function for this problem? Thanks for reading my question, Mark
From: Matt J on 20 May 2010 10:00 "Mark Schelbergen" <mjewrik(a)hotmail.com> wrote in message <ht3c9g$8ko$1(a)fred.mathworks.com>... > I use the equation below: > M=r x F (all vectors) > The moment; M and the arm; r are known, is there a way to calculate the force; F? ===================== No, there is no unique solution for F. You can convert this equation to a matrix equation using the function xprodmat below R=xprodmat(r); M=R*F; but the matrix R will always be singular. function A=xprodmat(a) %Matrix representation of a cross product % % A=xprodmat(a) % %in: % % a: 3D vector % %out: % % A: a matrix such that A*b=cross(a,b) if length(a)<3, v(a)=0; end ax=a(1); ay=a(2); az=a(3); A=zeros(3); A(2,1)=az; A(1,2)=-az; A(3,1)=-ay; A(1,3)=ay; A(3,2)=ax; A(2,3)=-ax;
From: Roger Stafford on 20 May 2010 10:20 "Mark Schelbergen" <mjewrik(a)hotmail.com> wrote in message <ht3c9g$8ko$1(a)fred.mathworks.com>... > I use the equation below: > M=r x F (all vectors) > The moment; M and the arm; r are known, is there a way to calculate the force; F? > Does matlab has a function for this problem? > > Thanks for reading my question, Mark Matt J is right. Any vector F2 which is given by F2 = cross(M,r)/dot(r,r)+k*r where k is any scalar whatever, will be a solution. To see this, just take the cross product of r and such an F2 and you will always get M. Roger Stafford
From: Mark Schelbergen on 25 May 2010 09:10 what is wrong with this: F2=uv(cross(M,r))*norm(M)/norm(r); where uv() is af function to determine the unit vector
From: Matt J on 25 May 2010 10:41 "Mark Schelbergen" <mjewrik(a)hotmail.com> wrote in message <htgi7t$3jq$1(a)fred.mathworks.com>... > what is wrong with this: > > F2=uv(cross(M,r))*norm(M)/norm(r); > > where uv() is af function to determine the unit vector As we've been saying, it is only 1 of an infinite number of possible solutions.
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