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From: bos1234 on 8 Jun 2010 00:09
[IMG]http://i50.tinypic.com/28sbn6f.png[/IMG]
From: bos1234 on 8 Jun 2010 00:35
>Please refer to the below picture for my question.
[IMG]http://i50.tinypic.com/28sbn6f.png[/IMG]
>
From: Tim Wescott on 8 Jun 2010 02:08
On 06/07/2010 09:09 PM, bos1234 wrote:
> [IMG]http://i50.tinypic.com/28sbn6f.png[/IMG]

Because the z transform tables are in the form z / (z - d), which
transforms to u(n) * d^n. 1 / (z - d) transforms to u(n-1) * d^(n-1),
which is awkward.

So you want to do your partial fraction expansion such that the result
is convenient.

What's the book? I know that's how I did it in mine.

--
Tim Wescott
Control system and signal processing consulting
www.wescottdesign.com
From: Jerry Avins on 8 Jun 2010 09:38
On 6/8/2010 12:09 AM, bos1234 wrote:
> [IMG]http://i50.tinypic.com/28sbn6f.png[/IMG]

You need a z in the numerator. To keep the denominator simple (as you
did), you have to put it there explicitly.

Jerry
--
Engineering is the art of making what you want from things you can get.
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From: Clay on 8 Jun 2010 11:15
On Jun 8, 12:35 am, "bos1234" <suren130(a)n_o_s_p_a_m.gmail.com> wrote:
> >Please refer to the below picture for my question.
>
> [IMG]http://i50.tinypic.com/28sbn6f.png[/IMG]
>
>
>
> - Hide quoted text -
>
> - Show quoted text -

There's an entire theory about how to do partial fraction expansion.
See here:

http://en.wikipedia.org/wiki/Partial_fraction

Just like with integration, you want to break your complicated product
into a sum of simpler pieces where each piece can be handled easily.
I.e., by lookup in a table. Otherwise you will do contour integration,
but even applying the Cauchy Goursat theorem is simplified via partial
fraction decomposition.

IHTH,
Clay


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