From: lucabenzo on
Hi everybody, I hope someone can help me with this...

Let a_k, b_k \in \mathbb{R}^n.

I know:

1) \lim_{k \rightarrow \infty}(a_k) exists

2)\lim_{k \rightarrow \infty}(a_k + b_k) exists.

Can I conclude that \lim_{k \rightarrow \infty}(b_k) exist? If it is
true, how can I prove this?

Thank you
From: Tonico on
On Jul 18, 11:53 am, lucabenzo <neblina.l...(a)libero.it> wrote:
> Hi everybody, I hope someone can help me with this...
>
> Let a_k, b_k \in \mathbb{R}^n.
>
> I know:
>
> 1) \lim_{k \rightarrow \infty}(a_k) exists
>
> 2)\lim_{k \rightarrow \infty}(a_k + b_k) exists.
>
> Can I conclude that \lim_{k \rightarrow \infty}(b_k) exist? If it is
> true, how can I prove this?
>
> Thank you



b_k = (a_k + b_k) - a_k , difference of converging sequences ==> it
converges and by arithmetic of limits its limit is the difference of
the limits.

Claim: if A = lim a_k, B = lim b_k exist, then exist both lim (a_k +
b_k) and
lim (a_k - b_k) , and their limit is A + B, A - B resp.

Proof: let e > 0 ==> there exist N_1, N_2 in N s.t.

1) for all n > N_1 , |a_n - A| < e/2

2) for all n > N_2 , |b_n - B| < e/2

Take M > max (N_1, N_2)==> for all n > M:

|a_n + b_n - (A + B)| <= |a_n - A| + |b_n - B| < e.

Tonio

Tonio