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From: M.A.Fajjal on 26 Feb 2010 01:06
> In article
> <1576618433.270690.1267134120146.JavaMail.root(a)gallium
> .mathforum.org>,
> M.A.Fajjal <h2maf(a)yahoo.com> wrote:
>
> > Evaluate
> >
> > limit((sum(exp((-1)^k*(Sum(ln(k0-1)/(-1)^k0, k0 = 2
> .. k))), k = 2 ..
> > n))/sqrt(n), n = infinity)
>
> Looks like it goes to infinity. Better denominator
> may be n^(3/2) .
>
> --
> G. A. Edgar
>
Thanks

It should be

limit(sum(1/(exp((-1)^k*(Sum(ln(k0-1)/(-1)^k0, k0 = 2 .. k)))*sqrt(n)), k = 2 .. n), n = infinity)

I think it goes to 2
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