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From: Mr. CFD on 22 Jun 2010 05:09
Hi,

a=[ .41 0.5 1 .71 1 1 0.05
.42 0.8 2 .22 2 2 0.05
.53 0.9 3 .43 3 3 0.01
.56 0.8 4 .84 4 4 0.05] ;

b=[1 2 3 4 5 6 7]

I'm trying to write a code whereby we can detect and delete duplicate data in column 'a'. For example we can see that a(:,3)==a(:,5)==a(:,6).

I want to delete the repeating data in column in a(:,5) and a(:,6) only [not a(:,3), which is the first time we get this data]. I need to then modify variable b by using the index 5 and 6 to delete the corresponding value in b, such that b becomes b=[1 2 3 4 7].

I have tried using unique and histc but just get into a big mess. I'm sure there is a simple work around to this. Can you please suggest a possible solution?
From: Oleg Komarov on 22 Jun 2010 07:00
"Mr. CFD" <s2108860(a)student.rmit.edu.au> wrote in message <hvpujh$p80$1(a)fred.mathworks.com>...
> Hi,
>
> a=[ .41 0.5 1 .71 1 1 0.05
> .42 0.8 2 .22 2 2 0.05
> .53 0.9 3 .43 3 3 0.01
> .56 0.8 4 .84 4 4 0.05] ;
>
> b=[1 2 3 4 5 6 7]
>
> I'm trying to write a code whereby we can detect and delete duplicate data in column 'a'. For example we can see that a(:,3)==a(:,5)==a(:,6).
>
> I want to delete the repeating data in column in a(:,5) and a(:,6) only [not a(:,3), which is the first time we get this data]. I need to then modify variable b by using the index 5 and 6 to delete the corresponding value in b, such that b becomes b=[1 2 3 4 7].
>
> I have tried using unique and histc but just get into a big mess. I'm sure there is a simple work around to this. Can you please suggest a possible solution?

[Out,b] = unique(a.','rows','first');
Out = Out.';

Up to you if you want to sort.

Oleg
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