Prev: select last field of line (cut/sed/awk etc)
Next: m to n or just n
From: Moody on 13 Jan 2010 03:49
On Jan 12, 6:52 pm, Stephane CHAZELAS <stephane_chaze...(a)yahoo.fr>
wrote:
> 2010-01-12, 00:04(+00), Kevin Collins:
> [...]> The problem above is that the '$$' in '(echo $$)' is expanded by the parent
> > shell before the sub-shell is spawned, which is why the same value shows up. I
> > can't think of a way to get the desired test accomplished :)
>
> [...]
>
> No, it's not, it's expanded by the subshell that may or may not
> be a child process. Any other pid than $$ and $! are the shell's
> internal cuisine's, one shouldn't need to deal with those.
>
> You can always use:
>
> sh -c '...whatever with "$$"...'
>
> if you want to start a new shell and have a different $$.
>
> --
> Stéphane

Yes,

It works like I needed...

$ echo $$
21320
$ sh -c 'echo $$'
21348
$


thanks.

BB
First  |  Prev  | 
Pages: 1 2 3 4 5
Prev: select last field of line (cut/sed/awk etc)
Next: m to n or just n