From: Alex on
Hello I am using the normpdf function to plot gaussian distributions for specific mean and std values. I have noticed that when sigma is small sigma<0.5 the normpdf returns values that are higher than 1 (which of course is not correct).

Do you know what might be wrong?

Best Regards
Alex.
From: Bruno Luong on
"Alex " <alaios(a)yahoo.com> wrote in message <hstpu4$k5h$1(a)fred.mathworks.com>...
> Hello I am using the normpdf function to plot gaussian distributions for specific mean and std values. I have noticed that when sigma is small sigma<0.5 the normpdf returns values that are higher than 1 (which of course is not correct).
>

Why "of course is not correct"? The integral of pdf must be 1 but the value *can* of course get higher than 1. In fact the center value goes to infinity when sigma goes to zero. See the doc if you haven't sure about the formula.

Bruno
From: Wayne King on
"Alex " <alaios(a)yahoo.com> wrote in message <hstpu4$k5h$1(a)fred.mathworks.com>...
> Hello I am using the normpdf function to plot gaussian distributions for specific mean and std values. I have noticed that when sigma is small sigma<0.5 the normpdf returns values that are higher than 1 (which of course is not correct).
>
> Do you know what might be wrong?
>
> Best Regards
> Alex.

Hi Alex, you should keep in mind that you are looking at a probability density function, not a probability mass function. There is no requirement that the values of a probability density function be less than or equal to one, only that the function integrates to one. Those are very different things.

For example, consider a uniform random variable on the interval [0, 1/2]. The value of the pdf over that interval is 2. Note that the integral is equal to one.

Wayne
From: Alex on
"Bruno Luong" <b.luong(a)fogale.findmycountry> wrote in message <hstr94$gue$1(a)fred.mathworks.com>...
> "Alex " <alaios(a)yahoo.com> wrote in message <hstpu4$k5h$1(a)fred.mathworks.com>...
> > Hello I am using the normpdf function to plot gaussian distributions for specific mean and std values. I have noticed that when sigma is small sigma<0.5 the normpdf returns values that are higher than 1 (which of course is not correct).
> >
>
> Why "of course is not correct"? The integral of pdf must be 1 but the value *can* of course get higher than 1. In fact the center value goes to infinity when sigma goes to zero. See the doc if you haven't sure about the formula.
>
> Bruno

Thanks for your replies. I thought pdf was a way of finding out what is the percentage of rolling the number 2 in a (0,3) standard deviation? So far I was getting this reply by checking what was the y-value after finding where x-value (2 in this example) is.

In that sense if normpdf returns number over 1 i could not translate this to the percentage or could I?

Best Regards
Thanks for the support
From: Torsten Hennig on
> "Bruno Luong" <b.luong(a)fogale.findmycountry> wrote in
> message <hstr94$gue$1(a)fred.mathworks.com>...
> > "Alex " <alaios(a)yahoo.com> wrote in message
> <hstpu4$k5h$1(a)fred.mathworks.com>...
> > > Hello I am using the normpdf function to plot
> gaussian distributions for specific mean and std
> values. I have noticed that when sigma is small
> sigma<0.5 the normpdf returns values that are higher
> than 1 (which of course is not correct).
> > >
> >
> > Why "of course is not correct"? The integral of pdf
> must be 1 but the value *can* of course get higher
> than 1. In fact the center value goes to infinity
> when sigma goes to zero. See the doc if you haven't
> sure about the formula.
> >
> > Bruno
>
> Thanks for your replies. I thought pdf was a way of
> finding out what is the percentage of rolling the
> number 2 in a (0,3) standard deviation?

The percentage of rolling the number 2 with a fair
six-sided die is 100/6.
What exactly is the problem you are trying to solve
with the normal distribution ?

> So far I was
> getting this reply by checking what was the y-value
> after finding where x-value (2 in this example) is.
>
> In that sense if normpdf returns number over 1 i
> could not translate this to the percentage or could
> I?
>
> Best Regards
> Thanks for the support

Best wishes
Torsten.