From: Kent Holing on
Given any polynomial equation of degree 8 and with rational coefficients. Can anybody provide criteria for the number of classical constructible roots of the given equation? (From Galois theory (group) we can tell when the octicequation is algebraically solvable or not.)

Of course, it is simple starting with a quartic eqaution to give examples of equation of degree 8 having either 0 or 8 constructible roots. (An irreducibel quartic with rational coefficients have either 0 or 4 constructible roots. Constructible roots exists if and only if the cubic resolvent of the quartic is reducible (has at leat one rational root).)

Best regards,
Kent Holing
NORWAY
From: What you are reading is Philosophy and P Versus NP. on
On Apr 1, 6:12 am, Kent Holing <K...(a)statoil.com> wrote:
> Given any polynomial equation of degree 8 and with rational coefficients. Can anybody provide criteria for the number of classical constructible roots of the given equation? (From Galois theory (group) we can tell when the octicequation is algebraically solvable or not.)
>
> Of course, it is simple starting with a quartic eqaution to give examples of equation of degree 8 having either 0 or 8 constructible roots. (An irreducibel quartic with rational coefficients have either 0 or 4 constructible roots. Constructible roots exists if and only if the cubic resolvent of the quartic is reducible (has at leat one rational root).)
Results 1 - 10 for polynomial equation of degree 8 and with rational
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From: I.M. Soloveichik on
> Given any polynomial equation of degree 8 and with
> rational coefficients. Can anybody provide criteria
> for the number of classical constructible roots of
> the given equation?

Factor the octic into irreducibles. For those irreducible factors with Galois group of order a power of 2, the roots are constructible.

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