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From: Sanjiv on 9 Nov 2009 09:26
i am doing my ME chemical engineering.

I want to solve the reaction rate equations using ode45 (Runge-kutta methode)

my reaction scheme-

A __k1____ B ____k2____ C ___k3____ D
| | |
|_____________| |
|k4 |
| | k7
E |
| |
| k5 |
F__________________ G
k6
rate equations are -

dCa/dt=-k1Ca

dCf/dt=k5Ce - k6Cf

dCg/dt= -k6Cf + k6Cf

dCd/dt= k7Cg + k3Cc

i have acheived the rate constant values of :
k5=0.23
k6 =0.24
k7=0.27
k3+k7 = 0.88

calculate values of k3, k4,k1 ,k2

know that Ca=0.04mol.dm-3



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