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From: Tom Lane on 24 May 2010 09:48
> I calculated power (S(:,1:49152)) over a specific frequency range.Then I
> used [y,x]=hist((S(1,1:49152)),200) to divide the power of the first
> frequency into 200 equally sized bins, so I have the pdf (plot(x,y)).I
> need to draw the power-likelihood distribution in the given frequency. So,
> in order to calculate y-axis(that is the likelihood) what I did is to
> divide the number of observations in each one of the 200 bins with the
> total number of observations which is 49152.

Naimead, it sounds like you are just looking for a proper density (one that
integrates to one). In that case you should divide by the product of the
number of observations and the bin width.

-- Tom


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