probability has holes seriously and please read before you makea comment!
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From: Tim Little on 1 Dec 2009 19:57 On 2009-12-01, eestath <stathopoulosee(a)gmail.com> wrote: > case 1: a number has as its factor 2 : probability 1/2 > case 2: a number has as its factor 2 and 3 : probability 1/ > (2*3) [...] Case 0: a number does not have 2 as a factor > case 3: a number has as its factor 2 and 3 and 5 : probability 1/ > (2*3*5) > ... > > if we cover every case probabilities add up to 1! > > So 1=1/2+1/(2*3)+1/(2*3*5)+..... Wow, you need to learn how to do basic probability. Firstly, you've excluded all the odd numbers. Secondly, you've used a formula for disjoint events for cases that are not disjoint - in fact, about as non-disjoint as you can get. Once you include the odd numbers and cease using a formula for disjoint probabilities, you get the correct (but trivial) 1 = 1/2 + 1/2. - Tim |