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From: Leandro Callegari Coelho on 27 Apr 2010 13:52
On Apr 27, 9:34 am, "Matt Fig" <spama...(a)yahoo.com> wrote:
> Something like this:
>
> N = 10;
>
> for jj = 2:8
>     T = nchoosek(1:N,jj);
>
>     for ii = 1:size(T,1)
>         fprintf(['x%i',repmat(' + x%i',1,size(T,2)-1),'\n'],T(ii,:))
>     end
>     fprintf('\n\n\n')
> end

Matt, thanks a lot. It works, I just need to adapt it to my equations.
I really appreciate your attention.
From: dpb on 27 Apr 2010 16:25
Leandro Callegari Coelho wrote:
> On Apr 27, 9:34 am, "Matt Fig" <spama...(a)yahoo.com> wrote:
>> Something like this:
>>
>> N = 10;
>>
>> for jj = 2:8
>> T = nchoosek(1:N,jj);
....
>
> Matt, thanks a lot. It works, I just need to adapt it to my equations.
> I really appreciate your attention.

for jj = 2:8
T = nchoosek(1:N,jj);

looks somehow remarkably similar to dpb's hint to explore

for idx=1:N
nchoosek(1:N,idx)

:)

--

From: Adam Fisher on 27 Apr 2010 16:59
dpb <none(a)non.net> wrote in message <hr7hat$7kd$1(a)news.eternal-september.org>...
> Leandro Callegari Coelho wrote:
> > On Apr 27, 9:34 am, "Matt Fig" <spama...(a)yahoo.com> wrote:
> >> Something like this:
> >>
> >> N = 10;
> >>
> >> for jj = 2:8
> >> T = nchoosek(1:N,jj);
> ...
> >
> > Matt, thanks a lot. It works, I just need to adapt it to my equations.
> > I really appreciate your attention.
>
> for jj = 2:8
> T = nchoosek(1:N,jj);
>
> looks somehow remarkably similar to dpb's hint to explore
>
> for idx=1:N
> nchoosek(1:N,idx)
>
> :)
>
> --
I went with
N=[1 2 3 4];
len=length(N);
for i =0:1:2^(len)-1
subset=dec2bin(i,len)=='1';
for j= N(subset)
fprintf(' + x%d ', j);
end
fprintf('=1\n');
end

if you don't want the empty set (ie =1) just switch the loop over i to start with 1
I also changed N from a struct to a vector
From: Leandro Callegari Coelho on 27 Apr 2010 17:35
Guys, since you're posting here again, I'll ask your help once again.
Turns out the equation I'm trying to write is way too hard to me.

Take a look at the equation here: http://twitpic.com/1iy2bu
Using your ideas I could almost finish the left side.

Explaining from the right to the left:
Big-fancy t can be small, i.e 3
Big-fancy M is what we're using N here, so it can be something like 5.

(for the ones that are curious this equation avoids subtours on a
vehicle routing model)

Anyone with enough time to tackle this?
From: Leandro Callegari Coelho on 28 Apr 2010 08:44
On Apr 27, 1:35 pm, Leandro Callegari Coelho <leandro...(a)gmail.com>
wrote:
> Guys, since you're posting here again, I'll ask your help once again.
> Turns out the equation I'm trying to write is way too hard to me.
>
> Take a look at the equation here:http://twitpic.com/1iy2bu
> Using your ideas I could almost finish the left side.
>
> Explaining from the right to the left:
> Big-fancy t can be small, i.e 3
> Big-fancy M is what we're using N here, so it can be something like 5.
>
> (for the ones that are curious this equation avoids subtours on a
> vehicle routing model)
>
> Anyone with enough time to tackle this?

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