From: ImageAnalyst on 28 Mar 2010 10:53 On Mar 28, 10:51 am, ImageAnalyst <imageanal...(a)mailinator.com> wrote: > Statistically, is that any different than just getting the 10,000 > numbers directly and immediately via > > randomSample = randn(1,10000) > > ??? > Either way you end up with 10000 normally distributed random numbers, > right? ------------------------------------------------------- Actually I reread Jan's message and realize that I'm saying the same thing he did. Sorry Jan.
From: Jan Simon on 28 Mar 2010 11:27 Dear ImageAnalyst! > Actually I reread Jan's message and realize that I'm saying the same > thing he did. Sorry Jan. Nice try. *I* have invented the "hyper-virtual memory" and a method, to efficiently pick elements from arrays, which occupy zillions of bytes. No chance to participate in the license fees! Sorry, ImageAnalyst. Kind regards, Jan
From: ImageAnalyst on 28 Mar 2010 13:19 On Mar 28, 11:27 am, "Jan Simon" <matlab.THIS_Y...(a)nMINUSsimon.de> wrote: > Dear ImageAnalyst! > > > Actually I reread Jan's message and realize that I'm saying the same > > thing he did. Sorry Jan. > > Nice try. > *I* have invented the "hyper-virtual memory" and a method, to efficiently pick elements from arrays, which occupy zillions of bytes. No chance to participate in the license fees! Sorry, ImageAnalyst. > > Kind regards, Jan --------------------------------------------------------------------- Jan, that's okay. I'm still very busy with my "Mind reading crystal ball toolbox." It will be sort of like MindFlex (http:// www.mindflexgames.com/) on steroids. So, once that's completed, I should have plenty of license fees rolling it.
From: Rajeev Narayanan on 28 Mar 2010 16:23 Hello All, Thanks for all the information. The solution pick=randn(1,10000) will generate some 10000 random number, but i want to pick from the element p which i have already generated. I think i am confusing you people. Here is the code which i am using to generate p randn('state', sum(clock)); p = zeros(1, 3^11); T= 0.00000001 for k= 1:3^11 p(k) = sqrt(T)*randn end Now from 'p' i need to pick some 10000 samples. Hope you understand the question. Thanks, Rajeev ImageAnalyst <imageanalyst(a)mailinator.com> wrote in message <aecfa453-be2b-4c83-9fec-b4c4d7ef0f71(a)g10g2000yqh.googlegroups.com>... > On Mar 28, 10:51 am, ImageAnalyst <imageanal...(a)mailinator.com> wrote: > > Statistically, is that any different than just getting the 10,000 > > numbers directly and immediately via > > > > randomSample = randn(1,10000) > > > > ??? > > Either way you end up with 10000 normally distributed random numbers, > > right? > > ------------------------------------------------------- > Actually I reread Jan's message and realize that I'm saying the same > thing he did. Sorry Jan.
From: forkandwait w on 28 Mar 2010 16:32 "Rajeev Narayanan" <rite2rajeev(a)gmail.com> wrote in message <hoodr9$ro8$1(a)fred.mathworks.com>... > Hello All, > > Thanks for all the information. The solution pick=randn(1,10000) will generate some 10000 random number, but i want to pick from the element p which i have already generated. randsample() seems to fit your needs. Have you tried it?
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