regular expression
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From: "Tanel Tammik" on 1 Jun 2010 11:19 How to check with regular expression (preg) if string has: 1. only letters 2. only letters and spaces Br Tanel
From: Adam Richardson on 1 Jun 2010 11:27 On Tue, Jun 1, 2010 at 11:19 AM, Tanel Tammik <keevitaja(a)gmail.com> wrote: > How to check with regular expression (preg) if string has: > > 1. only letters > 2. only letters and spaces > > Br > Tanel > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > $re1 = '/^[a-zA-Z]+$/'; $re2 = '/^[a-zA-Z ]+$/'; Adam -- Nephtali: PHP web framework that functions beautifully http://nephtaliproject.com
From: Ashley Sheridan on 1 Jun 2010 11:29 On Tue, 2010-06-01 at 18:19 +0300, Tanel Tammik wrote: > How to check with regular expression (preg) if string has: > > 1. only letters > 2. only letters and spaces > > Br > Tanel > > > Use preg_match() to find an expression within a string. You can use something like this to grab check if a string contains only letters or numbers: if(preg_match('/^[a-zA-Z0-9]+$/'), $string) { } Thanks, Ash http://www.ashleysheridan.co.uk
From: Richard Quadling on 1 Jun 2010 11:31 $re1 = '/^[a-z]++$/i'; $re2 = '/^[a-z ]++$/i'; -- ----- Richard Quadling "Standing on the shoulders of some very clever giants!" EE : http://www.experts-exchange.com/M_248814.html EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731 ZOPA : http://uk.zopa.com/member/RQuadling
From: Ashley Sheridan on 1 Jun 2010 11:33
On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote: > $re1 = '/^[a-z]++$/i'; > $re2 = '/^[a-z ]++$/i'; > > > > -- > ----- > Richard Quadling > "Standing on the shoulders of some very clever giants!" > EE : http://www.experts-exchange.com/M_248814.html > EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp > Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731 > ZOPA : http://uk.zopa.com/member/RQuadling > Why the double ++ in the expressions there? Surely one + would match the 1 or more characters that you need and the second one would just be surplus? Thanks, Ash http://www.ashleysheridan.co.uk |