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From: the cyclist on 20 Oct 2009 09:08
"Johan-Mark Sikkema" <johanmark82(a)gmail.com> wrote in message <hbkcca$4r7$1(a)fred.mathworks.com>...
> Hi,
>
> I have a vector of values Ar, then I calculate a value Re1 with a logical vector so for certain vector values Re is calculated otherwise 0 is put in the vector. The vector Re1 is used to calculate a vector Cd1.
> I do this to create 3 vectors Re and 3 vectors Cd. at the end I add the vectors with Re = Re1 + Re2 +Re3, and I do the same for Cd.
>
> Here's and example of code to show the logic.
> -----------------------------
> Ar =[30 500 90000]
> Re1 = ((Ar <36).*Ar)./18 % the part (Ar <36) gives the logical vector [1 0 0]
> Cd1 = 24./Re1
> -----------------------------end of code segement!
>
> The result is a vector Re1 = [14.4 Inf Inf ], because of the 0 elements in vector Re1 we devide 24 with.
> This is a problem because every vector element gets replaced by Inf when adding the vectors at the end, this would not happen with 0's (zeroes).
>
> Is there a method of replacing the Inf values in the vector by 0's but leaving the values that are not Inf? so Re1 = [14.4 0 0 ], in stead of [14.4 Inf Inf].
>
> I've tried things with isinf(Re1), but this replaces the 14.4 element by 0 and gives 1's for the Inf elements.
>
> P.S. I don't want to use any if statements to solve this problem!
>
> with kind regards,
> Johan-Mark

You almost got there!

>> Re1(isinf(Re1)) = 0;
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