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From: Jack Shown on 19 Dec 2009 22:32
On Dec 19, 1:46 am, mop2 <inva...(a)mail.address> wrote:
> On Sat, 19 Dec 2009 05:36:42 -0200, Jack Shown <jacksh...(a)gmail.com> wrote:
> > Hi Janis,  I think that's exactly what I tried (as I mentioned in my
> > previous post) but I gave yours a whirl anyway and it still did not
> > substitute.  I put what you wrote into a small shell script and ran it
> > with bash -x to see it execute and the command output looks like I
> > think it should:
>
> >    + sed -e 's/ width="[0-9]\+"/ width="256"/' -e 's/ height="[0-9]\
> > +"/ height="192"/'
>
> > I appreciate your efforts.
>
> > Jack
>
> $ bash -version|head -n1;sed --version|head -n1
> GNU bash, version 4.0.35(1)-release (i686-pc-linux-gnu)
> GNU sed version 4.2.1
> $
>
> $ cat file
> #------
> WIDTH=400
> HEIGHT=20
>
> sed '
> s/ width="[0-9]\+"/ width="'$WIDTH'"/
> s/ height="[0-9]\+"/  height="'$HEIGHT'"/
> ' file
>
> return
>
> <zzzzz width="33" yyyyy height="555" wwwwww>
> #----------------
>
> $ . ./file
> #------
> WIDTH=400
> HEIGHT=20
>
> sed '
> s/ width="[0-9]\+"/ width="'$WIDTH'"/
> s/ height="[0-9]\+"/  height="'$HEIGHT'"/
> ' file
>
> return
>
> <zzzzz width="400" yyyyy  height="20" wwwwww>
> #----------------
>
> $

It must be that my version of sed is just an old version because it
doesn't permit the '--version' nor does the output from strings /usr/
bin/sed show any kind of version although I did find "2003" in the
output. Thanks for trying to help. I really appreciate it.
From: Kevin Collins on 23 Dec 2009 14:11
On 2009-12-19, Jack Shown <jackshown(a)gmail.com> wrote:
> On Dec 18, 7:22�pm, Barry Margolin <bar...(a)alum.mit.edu> wrote:
>> In article
>> <4f1bc9a0-41c6-44a2-bca3-5358b51af...(a)g1g2000pra.googlegroups.com>,
>> �Jack Shown <jacksh...(a)gmail.com> wrote:
>>
>> > I have files that contain strings such as: �width="???" height="???"
>> > where the question marks represent positive integers of either two or
>> > three digits. Similar strings do exist but only once in each file does
>> > " width=" and " height=" exist. If I don't know where this string
>> > exists for sure, is there anyway to obtain those values and replace
>> > them based on their aspect ratio? �I don't need the aspect ratio
>> > conversion math, of course, just the extraction and the replacement.
>> > I'm using bash but perl or python would work too of course. �Thx.
>>
>> Does this do what you want:
>>
>> WIDTH=80
>> HEIGHT=24
>> sed -e 's/width="\?+\"/width="'$WIDTH'"/' -e
>> 's/height="\?+\"/height="'$HEIGHT'"/' filename > filename.new
>>
>> --
>> Barry Margolin, bar...(a)alum.mit.edu
>> Arlington, MA
>> *** PLEASE post questions in newsgroups, not directly to me ***
>> *** PLEASE don't copy me on replies, I'll read them in the group ***
>
> Hi Barry,
>
> That looked very promising but, unfortunately, the values in the input
> file remained unmodified.

Of course the values in your input file remain unchanged - this is sed and it
is redirecting output to a new file ("filename.new" in the code above).

You can use perl with in-line editing to change the source file itself:

perl -pi -e '

# adjust the aspecy by?
$aspect = .5;

# for height
if (/\bheight="(\d+)"/)
{
$h = int($1 * $aspect);
s/\bheight="$1"/height="$h"/;
}

# for height
if (/\bwidth="(\d+)"/)
{
$w = int($1 * $aspect);
s/\bwidth="$1"/width="$w"/;
}
' your_file_name

This should do what you want pretty handily, I think.

If it were me, I would be tempted to make the matches case-insensitive (/.../i,
s/.../.../i), since it appears to be HTML and the case could change.

Kevin
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