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From: mobileT83 T on 21 May 2010 06:38
This worked perfectlly!!! I just had trouble testing it. Is there any way I could get vectors M and N returned in the correct order corresponding to
M N L
1 1 [random values]
2 1 [random values]
3 1 [random values]
4 1 [random values]
1 2 [random values]
2 2 [random values]
3 2 [random values]
4 2 [random values]

L is what was returned by a = reshape(A,[],L);

"Roger Stafford" <ellieandrogerxyzzy(a)mindspring.com.invalid> wrote in message <ht3tfb$aqm$1(a)fred.mathworks.com>...
> "mobileT83 T" <mobileT83(a)gmail.com> wrote in message <ht3mle$9re$1(a)fred.mathworks.com>...
> > I would like to take a MxNxL matrix and get a M*NxL matrix. I know I can do this with two for loops
> >
> > A = MxNxL
> > for ii = 1:N
> > for jj = 1:M
> >
> > a = A(jj,ii,:);
> >
> > end
> > end
> >
> > but I was hoping to you a reshape tool. And I want to keep the order given in this for loop.
> >
> > I found this but I don't know if it will help me... maybe I don't get it.
> > http://www.mathworks.com/matlabcentral/fileexchange/20255
> >
> > Thanks
> >
> > mobile
>
> Do:
>
> a = reshape(A,[],L);
>
> It is incompatible with the very notion of an M*N by L matrix to have the ordering you give from your for-loops. If I interpret your for-loop correctly, each set of L entries occurs in the most rapid ordering sequence, followed by the M and then the N entries. An M*N by L array doesn't work this way.
>
> Roger Stafford
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