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From: Chip Eastham on 10 May 2010 15:47
On May 6, 8:31 am, Chip Eastham <hardm...(a)gmail.com> wrote:
> On May 6, 6:40 am, rossum <rossu...(a)coldmail.com> wrote:
>
> > On Wed, 5 May 2010 23:32:06 -0700 (PDT), Erik Carlson
>
> > <eriksb...(a)yahoo.com> wrote:
> > >Here is a working example that uses a set of 5 letters {A, B, C, D, E}
> > >with the use of 3 blank spaces to start.
>
> > >_ _ _ D E C B B B B A E C C C C D A E E E E B D A A A A C B D D B
>
> > Why do you need the three blanks to start?  You can get the same
> > result with three D's in their place:
>
> >   D D D D E C B B B B A E C C C C D A E E E E B D A A A A C B D D B
>
> > rossum
>
> I think the use of blanks matters (to the OP) only in that it
> minimizes
> the count of letters used (because blanks, even internal ones, aren't
> counted).
>
> regards, chip

In fact with slight modification the five symbol
solution above can be converted into a circular
30 symbol arrangement without blanks that covers
all thirty required subsets (size 1-4):

D D D D E C...
B B B B A E...
C C C C D A...
E E E E B D...
A A A A C B...
(repeat)

This suggests that the five symbol case may be
so special that no others cases (of window length
4) exist without internal blanks. [Ten internal
blanks could be introduced here to replace the
inside pair of each 4-peat block, without any
change in the subsets covered.]

regards, chip
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