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From: Edwin on 12 Aug 2010 04:15
Hello everyone,
if I have two column vector for example
gm=[1:1:100]';
g=[1:1:21]';

Could someone please show me how can I subtract each row in gm by each row in g,
so I can get a new matrix with size 100x21 without using a for loop.


Regards
From: Carl on 12 Aug 2010 06:43
"Edwin " <onest30(a)gmail.com> wrote in message <i40air$grs$1(a)fred.mathworks.com>...
> Hello everyone,
> if I have two column vector for example
> gm=[1:1:100]';
> g=[1:1:21]';
>
> Could someone please show me how can I subtract each row in gm by each row in g,
> so I can get a new matrix with size 100x21 without using a for loop.
>
>
> Regards

Have a look at repmat you should be able to work out what to do from there.
From: Edwin on 12 Aug 2010 06:48
Thanks

just in case, this is what I did

Z=repmat(g,[1 size(gm,1)])-(ones(size(g,1),1))*gm';


Regards
From: Carl on 12 Aug 2010 09:04
"Edwin " <onest30(a)gmail.com> wrote in message <i40air$grs$1(a)fred.mathworks.com>...
> Hello everyone,
> if I have two column vector for example
> gm=[1:1:100]';
> g=[1:1:21]';
>
> Could someone please show me how can I subtract each row in gm by each row in g,
> so I can get a new matrix with size 100x21 without using a for loop.
>
>
> Regards

Have a look at repmat you should be able to work out what to do from there.
From: Matt J on 12 Aug 2010 10:43


Use BSXFUN

bsxfun(@minus,gm,g.');


Do not use REPMAT. It costs more memory than is necessary here.
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