t' = beta(t + vx/c^2
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From: glird on 15 Apr 2010 17:22 In Poincare's 1905 transformation equation, t' = beta(t + vx/c^2), t' is a time of system k and t and x are values of system K. The question is: Which system is moving and what is its direction? To me, the answer is: .. Cs k is moving to the left at -v. To others, perhaps including Einstein, system K is the moving system. What do you think? glird
From: ben6993 on 15 Apr 2010 18:14
On Apr 15, 10:22 pm, glird <gl...(a)aol.com> wrote: > In Poincare's 1905 transformation equation, t' = beta(t + vx/c^2), > t' is a time of system k and t and x are values of system K. > The question is: Which system is moving and what is its direction? > To me, the answer is: > . Cs k is moving to the left at -v. To others, perhaps including > Einstein, system K is the moving system. > What do you think? > > glird Einstein 1905 paper: "Now to the origin of one of the two systems (k) let a constant velocity v be imparted in the direction of the increasing x of the other stationary system (K), and let this velocity be communicated to the axes of the co-ordinates, the relevant measuring-rod, and the clocks." http://www.fourmilab.ch/etexts/einstein/specrel/www/ Para.3 Poincare 1905 paper: t' = kl(t + epsilon x) where k=1/sqrt(1-epsilon^2) l=1 Presumably, epsilon=v/c, though I can't find it explicitly stated as that. It says: by the way epsilon is a constant which defines the transformation k=1/sqrt(1-epsilon^2. Also, it says that t is the time before the transformation and t' is after the tranformation {Pardon any mis-translations from the French.} http://www.soso.ch/wissen/hist/SRT/P-1905-1.pdf |