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From: gobruins on 21 Oct 2009 12:55 Hi, I am learning multi-channel DDC techniques using FFT. My design is referenced to http://www.pentek.com/tutorials/15_4/digdown.cfm Something in this design I do not understand. The FFT will split the input stream into N(FFT size) bins equally spaced in frequency. Totally 4 FFTs are used so that the output data rate is fs/N*4. Followed by the FFT a compensation filter is used to flatten the frequency droop at the passband edge. What I do not understand is that after FFT each bin output is a bandpass signal whose center frequency is fs/N*k (k=0:N-1). Do we need a phase shifter to translate these bandpass signals down to baseband before applying the compensation filter? I am confused on this part, I appreciate for any help.
From: emeb on 21 Oct 2009 13:14 On Oct 21, 9:55 am, "gobruins" <chunmei.k...(a)gmail.com> wrote: > Hi, I am learning multi-channel DDC techniques using FFT. My design is > referenced tohttp://www.pentek.com/tutorials/15_4/digdown.cfm > Something in this design I do not understand. > The FFT will split the input stream into N(FFT size) bins equally spaced > in frequency. Totally 4 FFTs are used so that the output data rate is > fs/N*4. Followed by the FFT a compensation filter is used to flatten the > frequency droop at the passband edge. > What I do not understand is that after FFT each bin output is a bandpass > signal whose center frequency is fs/N*k (k=0:N-1). Do we need a phase > shifter to translate these bandpass signals down to baseband before > applying the compensation filter? > I am confused on this part, I appreciate for any help. What you're trying to build is called a "transmultiplexer". The Pentek article has oversimplified the structure somewhat, leaving out the polyphase filter that's usually placed on the input of the FFT. With the polyphase filter you won't need a compensation filter after the FFT. Do a bit of googling on the term transmultiplexer to get a better idea of how to build one. You might also throw in the name 'harris', since fred harris has written a lot about this structure - even has a pretty good book out on multi-rate systems which goes into a fair amount of detail on it. When properly implemented, a transmultiplexer converts each of the bandpass channels down to be centered at DC. Eric
From: gobruins on 21 Oct 2009 14:19 Thanks, I found a paper by fred Harris Digital Receivers and Transmitters Using Polyphase Filter Banks for Wireless Communications I will take a look. when you say "When properly implemented, a transmultiplexer converts each of the bandpass channels down to be centered at DC". is this by aliasing the pass band to baseband? >On Oct 21, 9:55=A0am, "gobruins" <chunmei.k...(a)gmail.com> wrote: >> Hi, I am learning multi-channel DDC techniques using FFT. My design is >> referenced tohttp://www.pentek.com/tutorials/15_4/digdown.cfm >> Something in this design I do not understand. >> The FFT will split the input stream into N(FFT size) bins equally spaced >> in frequency. Totally 4 FFTs are used so that the output data rate is >> fs/N*4. Followed by the FFT a compensation filter is used to flatten the >> frequency droop at the passband edge. >> What I do not understand is that after FFT each bin output is a bandpass >> signal whose center frequency is fs/N*k (k=3D0:N-1). Do we need a phase >> shifter to translate these bandpass signals down to baseband before >> applying the compensation filter? >> I am confused on this part, I appreciate for any help. > >What you're trying to build is called a "transmultiplexer". The Pentek >article has oversimplified the structure somewhat, leaving out the >polyphase filter that's usually placed on the input of the FFT. With >the polyphase filter you won't need a compensation filter after the >FFT. Do a bit of googling on the term transmultiplexer to get a better >idea of how to build one. You might also throw in the name 'harris', >since fred harris has written a lot about this structure - even has a >pretty good book out on multi-rate systems which goes into a fair >amount of detail on it. > >When properly implemented, a transmultiplexer converts each of the >bandpass channels down to be centered at DC. > >Eric >
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