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From: GregS on 16 Apr 2007 09:36 I need some assistance to figure out a problem. i was looking for an online calculator. I have a weigth mass, and I want to drop it at different heights, and compute the impact force. The impact area would also affect the actual force. Its about a 1 lb weight and a drop of 4 to 10 inches. I was planning on buying a load cell of 100 lbs capacity to try to measure this, and I wanted to know if this was enough. greg
From: Sam Wormley on 16 Apr 2007 09:45 GregS wrote: > I need some assistance to figure out a problem. i was looking for an online calculator. > I have a weigth mass, and I want to drop it at different heights, and compute > the impact force. The impact area would also affect the actual force. > Its about a 1 lb weight and a drop of 4 to 10 inches. I was planning on buying > a load cell of 100 lbs capacity to try to measure this, and I wanted to know if this > was enough. > > greg Try: http://hyperphysics.phy-astr.gsu.edu/hbase/impulse.html
From: GregS on 16 Apr 2007 10:33 In article <86LUh.58733$oV.58014(a)attbi_s21>, Sam Wormley <swormley1(a)mchsi.com> wrote: >GregS wrote: >> I need some assistance to figure out a problem. i was looking for an online > calculator. >> I have a weigth mass, and I want to drop it at different heights, and compute >> the impact force. The impact area would also affect the actual force. >> Its about a 1 lb weight and a drop of 4 to 10 inches. I was planning on > buying >> a load cell of 100 lbs capacity to try to measure this, and I wanted to know > if this >> was enough. >> >> greg > > > Try: http://hyperphysics.phy-astr.gsu.edu/hbase/impulse.html I have distance, but velocity is ???? greg
From: JWS on 16 Apr 2007 10:39 GregS wrote: > I need some assistance to figure out a problem. i was looking > for an online calculator. I have a weigth mass, and I want to > drop it at different heights, and compute the impact force. The > impact area would also affect the actual force. Its about a 1 > lb weight and a drop of 4 to 10 inches. I was planning on > buying a load cell of 100 lbs capacity to try to measure this, > and I wanted to know if this was enough. > greg The formula is F_dynamic t_fall --------- = 1 + ------- F_static t_sound in which F_dynamic = impact force F_static = force between the ground and the weight, when the weight is just lying on the ground t_fall = the fall time of the weight (= sqrt(2h/g)) t_sound = the time in which a sound wave runs through the weight, or L/v (L="height" of weight, v = speed of sound). Speed of sound in solids can be looked up in tables; e.g. in steel, 5000 m/sec. This assumes that your load cell is infinitely stiff, i.e., it does not act as some kind of cushion which absorbs energy from the fall, thereby reducing the impact force. I think that measuring impact forces is quite a challenge for experimenters. I'd be very interested in your results. See http://www.jw-stumpel.nl/bounce.html
From: Uncle Al on 16 Apr 2007 10:52 GregS wrote: > > In article <86LUh.58733$oV.58014(a)attbi_s21>, Sam Wormley <swormley1(a)mchsi.com> wrote: > >GregS wrote: > >> I need some assistance to figure out a problem. i was looking for an online > > calculator. > >> I have a weigth mass, and I want to drop it at different heights, and compute > >> the impact force. The impact area would also affect the actual force. > >> Its about a 1 lb weight and a drop of 4 to 10 inches. I was planning on > > buying > >> a load cell of 100 lbs capacity to try to measure this, and I wanted to know > > if this > >> was enough. > >> > >> greg > > > > > > Try: http://hyperphysics.phy-astr.gsu.edu/hbase/impulse.html > > I have distance, but velocity is ???? s = (at^2)/2 v = at a = one gee, corrected for your latitude and altitude above the geoid. g = (978.032677)[1+(0.00193185139)sin^2(lat)]/sqrt[1-(0.00669437999)sin^2(lat)] cm/sec^2 dg/dh = 0.000308766[1-(0.0014665)sin^2(lat)] cm/sec^2-meter r = geocentric radius a = free fall acceleration lat = latitude g = gravitational acceleration h = altitude above sea level s = distance t = time v = velocity You can add the ballistic coefficient if you want to trim decimal places. Since your mass is dense, your medium is not viscous, and your fall time is short, Stokes won't get you and you are nowhere near terminal velocity. -- Uncle Al http://www.mazepath.com/uncleal/ (Toxic URL! Unsafe for children and most mammals) http://www.mazepath.com/uncleal/lajos.htm#a2
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