where is the factorial value 1/2 of the exponent value in 10^500 #4.13 Correcting Math
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From: Archimedes Plutonium on 24 Jul 2010 02:29 Transfer Principle wrote: > solve 2x = log(x!) for x > > and then clicked on "use the base 10 logarithm." Though Wolfram > returns the trivial value x = 0, there is a graph, and one can > roll the mouse over the non-trivial solution: > > (268.087, 536.175) > > Thus, we find that 268! is approximately 10^536. > 268! = 10^536 Thanks, will store that for future use. I don't think there is a nucleus with 268 nucleons What I am fascinated with, is the chain of events that some years or months past where I picked 10^500, almost out of the blue, but of course it is so symmetrical, and come to find that a lucky pick is pretty close to where the boundary between finite and infinite really exists. When I picked 10^500 I was never cognizant that the Strong Nuclear Force is nonexistent there. Archimedes Plutonium http://www.iw.net/~a_plutonium/ whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |