From: Archimedes Plutonium on


Archimedes Plutonium wrote:
(snipped)
>
> Now in mathematics (i) is often regarded as being the equivalent of a
> 90
> degree rotation. Now if we can believe that to be true would suggest
> that in
> the 16Wheel or the 10^500Wheel that the number (i) is either to be the
> equator
> between the South Pole and heading back to the North Pole of 270
> degree radian.
> This suggests that (i) is itself a negative number. If (i) were at 90
> degree radian
> of the equator in the positive number realm, then (i) would likely be
> the number
> that is suggested from this sequence as the number 3162......
>
> sqrt9 = 3
> sqrt99 = 9.94
> sqrt999 = 31.60
> sqrt9999 = 99.99
> sqrt99999 = 316.22
> sqrt999999 = 999.99
> sqrt9999999 = 3162.27
>

My computer capabilities of these large exponents quickly give out.

In the approximations I have 2.71^97 yields the first two frontview
digits as
99.....

And the approx. of 3162 x 3.14 yields 99.....

So this suggests with some confidence that the square root of (i) is
likely to
be of some form of 3162.......

Again, what I want to achieve is a string of 9s as such 99999.....
since
-1 is 9999...... and thus fetching what (i) is in Euler's Identity.

Now I said in the posts that this is achievable since a proof that a
long string of
1111.....11111 in binary has prime factors. But another rally call for
achievability
is the fact that in Real Analysis, an equation of the form a^b*c =
99999...
where a, b are constants, and thus c has a proven solution.

So I have the first frontview digits of 99...... now I need to have a
computer fetch
a longer string of pure 9s. We can use pi and e up to 10^-500.

And the (i) may have a decimal point or binary point if necessary to
continue with the
string of pure 9s.

Now if this number 3162..... is truly the (i) value, then I do not
know whether that number
is on the positive finite hemisphere of the wheel of numbers or
whether it lies on the infinity=
negativenumbers hemisphere? If I had to guess, I would guess this
number (i) emerges on
the infinity=negativenumbers hemisphere. And I would further guess
that it is the 270 degree
radian equator line in the second hemisphere so as to make (i) a 90
degree rotation since
the equator is 90 degrees from the North Pole point. If that is so,
then the use of Euler's Identity would not only fix the value of (i)
but fix what the equator of 270 degree radian is.

I do not know what the value of the positive finite number hemisphere
equator is.

Now in a very old post of mine circa 1994, I remember posting a
question that the
negative numbers maybe far more abundant than the positive numbers.
This Number-Wheel
sort of hints that there is a possibility that the numbers on the
negativenumber hemisphere
can be a set that is far larger than the opposite hemisphere. Because
all the negative
numbers in decimal have repeating 9s such as 9999....9998 = -2 and if
the last number
of the finite positives is 099999.....99999 would mean that the number
3162..... is not even
registered in either hemisphere.

So if I have solved what the value of (i) is in terms of digits in a
number, it leaves a
vast new slew of questions and new problems.

But I do like this new idea of a Wheel of Numbers, for it shows what
numbers are
finite and have a working Algebra and what numbers have no Algebra
that is trustworthy.
Perhaps that is the key, in that the number 3162..... if it is (i) is
not trustworthy of being
(i). It reminds me of virtual particles in physics, where they come
into being to preserve
the laws of physics in quantum mechanics. And so are these numbers
"virtual numbers?"

Numbers like 9999....9999 =-1 seem sure footed, but what about numbers
like 5555...55
or 3161.... I suppose like anything in science, when a discovery is
made it may answer some
particular question and close the door on that question, but it also
opens up new questions
and new challenges.


Archimedes Plutonium
http://www.iw.net/~a_plutonium/
whole entire Universe is just one big atom
where dots of the electron-dot-cloud are galaxies