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From: Archimedes Plutonium on 9 Mar 2010 03:39 Archimedes Plutonium wrote: (snipped) > > Now in mathematics (i) is often regarded as being the equivalent of a > 90 > degree rotation. Now if we can believe that to be true would suggest > that in > the 16Wheel or the 10^500Wheel that the number (i) is either to be the > equator > between the South Pole and heading back to the North Pole of 270 > degree radian. > This suggests that (i) is itself a negative number. If (i) were at 90 > degree radian > of the equator in the positive number realm, then (i) would likely be > the number > that is suggested from this sequence as the number 3162...... > > sqrt9 = 3 > sqrt99 = 9.94 > sqrt999 = 31.60 > sqrt9999 = 99.99 > sqrt99999 = 316.22 > sqrt999999 = 999.99 > sqrt9999999 = 3162.27 > My computer capabilities of these large exponents quickly give out. In the approximations I have 2.71^97 yields the first two frontview digits as 99..... And the approx. of 3162 x 3.14 yields 99..... So this suggests with some confidence that the square root of (i) is likely to be of some form of 3162....... Again, what I want to achieve is a string of 9s as such 99999..... since -1 is 9999...... and thus fetching what (i) is in Euler's Identity. Now I said in the posts that this is achievable since a proof that a long string of 1111.....11111 in binary has prime factors. But another rally call for achievability is the fact that in Real Analysis, an equation of the form a^b*c = 99999... where a, b are constants, and thus c has a proven solution. So I have the first frontview digits of 99...... now I need to have a computer fetch a longer string of pure 9s. We can use pi and e up to 10^-500. And the (i) may have a decimal point or binary point if necessary to continue with the string of pure 9s. Now if this number 3162..... is truly the (i) value, then I do not know whether that number is on the positive finite hemisphere of the wheel of numbers or whether it lies on the infinity= negativenumbers hemisphere? If I had to guess, I would guess this number (i) emerges on the infinity=negativenumbers hemisphere. And I would further guess that it is the 270 degree radian equator line in the second hemisphere so as to make (i) a 90 degree rotation since the equator is 90 degrees from the North Pole point. If that is so, then the use of Euler's Identity would not only fix the value of (i) but fix what the equator of 270 degree radian is. I do not know what the value of the positive finite number hemisphere equator is. Now in a very old post of mine circa 1994, I remember posting a question that the negative numbers maybe far more abundant than the positive numbers. This Number-Wheel sort of hints that there is a possibility that the numbers on the negativenumber hemisphere can be a set that is far larger than the opposite hemisphere. Because all the negative numbers in decimal have repeating 9s such as 9999....9998 = -2 and if the last number of the finite positives is 099999.....99999 would mean that the number 3162..... is not even registered in either hemisphere. So if I have solved what the value of (i) is in terms of digits in a number, it leaves a vast new slew of questions and new problems. But I do like this new idea of a Wheel of Numbers, for it shows what numbers are finite and have a working Algebra and what numbers have no Algebra that is trustworthy. Perhaps that is the key, in that the number 3162..... if it is (i) is not trustworthy of being (i). It reminds me of virtual particles in physics, where they come into being to preserve the laws of physics in quantum mechanics. And so are these numbers "virtual numbers?" Numbers like 9999....9999 =-1 seem sure footed, but what about numbers like 5555...55 or 3161.... I suppose like anything in science, when a discovery is made it may answer some particular question and close the door on that question, but it also opens up new questions and new challenges. Archimedes Plutonium http://www.iw.net/~a_plutonium/ whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |