Number Wheel solves (i) Re: proof of unique solution to e^(pi)(i) = -1; #500 Correcting Math
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From: Archimedes Plutonium on 9 Mar 2010 15:14 David Bernier wrote: > > Do you want to have > 99999..99 = -1 ? > > David Bernier David, I was thinking prior to today that I needed a long string of 9s to solve Euler's Identity for (i). If we take the successive square root of 9s sqrt9 = 3 sqrt99 = 9.94 sqrt999 = 31.60 sqrt9999 = 99.99 sqrt99999 = 316.22 sqrt999999 = 999.99 sqrt9999999 = 3162.27 And coupled with the idea that -1 is 9999...9999 then we are presented with a solution of the numeric value of (i) in Euler's Identity. In old math, if you pop into the Euler's Identity (i) = 312...... things are going to fall apart real fast. Because in old math e and pi and (i) cannot produce a 9999....9999. But then old math never *precision defined finite*. So once you precision define Finite as say 10^500, then all the objections of solving Euler's Identity fade away. The number (i) of its first three digits in Frontview are 312..... which yields 2.71^97 = 99.... and where pi is 3.14 In New Math with a precise Finite an e^97 dispenses with all multiplications less than 10^-500 so that we need only a few digits of the digit string of pi and e when the exponent is 97. So this is the first time in Math history that the number (i) is written out in its numeric value. It is 312.... Where 312.... lies in the Number Wheel I am not sure. It must have something to do with a 90 degree rotation. But the numbers on the 10^500 Number Wheel are all those of 0 to 10^500 and then the negatives of those starting with 999..99=-1 and finishing with 9000..00 = -0999..99 Picture anyone drawing a Cartesian Coordinate System with 0 and let us say they stop with 10. So that there would be a 0 to 10 and then a 0 to -10. Now they folded this line segment into the shape of a wheel or circle. That is the Number Wheel. When math precisely defines Finite, then they must select a largest finite number. Then you have all the negatives of that set of positive finites. Plot them on a Cartesian Coordinate System then fold them into the shape of a Wheel or circle. Euler's Identity can be solved for all of these Number Wheels and where (i) has the numeric value of 312.... Archimedes Plutonium http://www.iw.net/~a_plutonium/ whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |