From: Paul B. Andersen on
On 17.02.2010 23:06, Henry Wilson DSc wrote:
> On Wed, 17 Feb 2010 13:10:56 +0100, "Paul B. Andersen"
> <paul.b.andersen(a)somewhere.no> wrote:
>
>> On 15.02.2010 23:24, Henry Wilson DSc wrote:
>>> On Mon, 15 Feb 2010 14:13:02 +0100, "Paul B. Andersen"
>>> <paul.b.andersen(a)somewhere.no> wrote:
>>>
>>>> On 12.02.2010 00:33, Henry Wilson DSc wrote:
>>>>> Paul and Jerry are standing together on the equator of an Earthlike planet,
>>>>> next to an optical fibre that encircles the planet, WHICH IS NOT ROTATING. Its
>>>>> circumference is 40 million metres.
>>>>>
>>>>> //===================C======================// optical fibre around equator
>>>>> _____________v<-_____p___q_______________________surface (actually curved)
>>>>>
>>>
>>> I recognized my mistake and immediately corrected it.
>>>
>>> The pulses that leave together arrive together.
>>>
>>> If you want to comment, use my later version in which the pulse arrival rates
>>> are different from both directions. The theory should be obvious to anyone with
>>> a higher IQ than inertial.
>>
>> "The pulses that leave together arrive together", but the pulses are
>> arriving at a different rate than those they arriving together with.
>>
>> It sure takes a high IQ to understand that! :-)
>
> Maybe you are having trouble with frames.
>
>
>>
>> BTW, in my previous posting I wrote:
>> | Yet again you have made a giant fool of yourself.
>> | I wonder how long it will take this time before you
>> | realize that you have made a giant, unbelievable stupid blunder.
>> |
>> | I bet it will take a very long time, and if it eventually should
>> | dawn to you, you will never admit it. What will you do then?
>> | Start a new thread with a modified 'experiment'? :-)
>>
>> Now we know what you did! :-)
>> You admitted your blunder, but couldn't admit that your
>> conclusion based on that blunder was wrong, so you had to
>> make an even bigger blunder to defend your wrong conclusion.
>>
>> Good to see that you still are able to invent new stupidities
>> and not only are recycling old ones.
>> This was definitely one of your better.
>>
>> Keep it up, the sky is the limit!
>
> ==//=================p---------q|====================//====optical tube
> ________________________earth____<-v__________________(actually curved)
>
> A pulse of light is emitted every 3.333 nanosecs by a source. The pulses, which
> are separated by 1 metre, are sent down an optical fibre that is wrapped around
> the earth.. There are 4000000 pulses around the equator.
>
> A pulse emitted at point q will travel leftward around the Earth through the
> fibre before reaching a detector at point p. During its travel time the Earth
> revolves by 62 metres.
>
> We will consider what happens when pulse N is emitted at point q. It will pass
> through point p then travel around the Earth before being finally absorbed
> again at point p.
> When it is emitted, there are 62 pulses between q and p. When pulse N reaches p
> the first time, there are say 61 pulses between p and q and 62 pulses have
> already passed through point p. There are 4000000-61 pulses around the earth
> at that instant between p and q. So another 61 + 4000000 - 41 pulses will reach
> p by the time N gets there. That makes 4000062 altogether.
> In the other direction, only 3999938 arrive in the same time.

Thus Spoke Doctor Ralph Rabbidge. :-)

As I said, the sky is the limit!
Close, but not quite there.
Go for it!

--
Paul

http://home.c2i.net/pb_andersen/
From: Henry Wilson DSc on
On Tue, 23 Feb 2010 12:28:28 +0100, "Paul B. Andersen"
<paul.b.andersen(a)somewhere.no> wrote:

>On 17.02.2010 23:06, Henry Wilson DSc wrote:
>> On Wed, 17 Feb 2010 13:10:56 +0100, "Paul B. Andersen"
>> <paul.b.andersen(a)somewhere.no> wrote:
>>
>>> On 15.02.2010 23:24, Henry Wilson DSc wrote:
>>>> On Mon, 15 Feb 2010 14:13:02 +0100, "Paul B. Andersen"
>>>> <paul.b.andersen(a)somewhere.no> wrote:
>>>>
>>>>> On 12.02.2010 00:33, Henry Wilson DSc wrote:
>>>>>> Paul and Jerry are standing together on the equator of an Earthlike planet,
>>>>>> next to an optical fibre that encircles the planet, WHICH IS NOT ROTATING. Its
>>>>>> circumference is 40 million metres.
>>>>>>
>>>>>> //===================C======================// optical fibre around equator
>>>>>> _____________v<-_____p___q_______________________surface (actually curved)
>>>>>>
>>>>
>>>> I recognized my mistake and immediately corrected it.
>>>>
>>>> The pulses that leave together arrive together.
>>>>
>>>> If you want to comment, use my later version in which the pulse arrival rates
>>>> are different from both directions. The theory should be obvious to anyone with
>>>> a higher IQ than inertial.
>>>
>>> "The pulses that leave together arrive together", but the pulses are
>>> arriving at a different rate than those they arriving together with.
>>>
>>> It sure takes a high IQ to understand that! :-)
>>
>> Maybe you are having trouble with frames.
>>
>>
>>>
>>> BTW, in my previous posting I wrote:
>>> | Yet again you have made a giant fool of yourself.
>>> | I wonder how long it will take this time before you
>>> | realize that you have made a giant, unbelievable stupid blunder.
>>> |
>>> | I bet it will take a very long time, and if it eventually should
>>> | dawn to you, you will never admit it. What will you do then?
>>> | Start a new thread with a modified 'experiment'? :-)
>>>
>>> Now we know what you did! :-)
>>> You admitted your blunder, but couldn't admit that your
>>> conclusion based on that blunder was wrong, so you had to
>>> make an even bigger blunder to defend your wrong conclusion.
>>>
>>> Good to see that you still are able to invent new stupidities
>>> and not only are recycling old ones.
>>> This was definitely one of your better.
>>>
>>> Keep it up, the sky is the limit!
>>
>> ==//=================p---------q|====================//====optical tube
>> ________________________earth____<-v__________________(actually curved)
>>
>> A pulse of light is emitted every 3.333 nanosecs by a source. The pulses, which
>> are separated by 1 metre, are sent down an optical fibre that is wrapped around
>> the earth.. There are 4000000 pulses around the equator.
>>
>> A pulse emitted at point q will travel leftward around the Earth through the
>> fibre before reaching a detector at point p. During its travel time the Earth
>> revolves by 62 metres.
>>
>> We will consider what happens when pulse N is emitted at point q. It will pass
>> through point p then travel around the Earth before being finally absorbed
>> again at point p.
>> When it is emitted, there are 62 pulses between q and p. When pulse N reaches p
>> the first time, there are say 61 pulses between p and q and 62 pulses have
>> already passed through point p. There are 4000000-61 pulses around the earth
>> at that instant between p and q. So another 61 + 4000000 - 61 pulses will reach
>> p by the time N gets there. That makes 4000062 altogether.
>> In the other direction, only 3999938 arrive in the same time.

(apologies, the '41' was an obvious typo)

>Thus Spoke Doctor Henry Wilson. :-)
>
>As I said, the sky is the limit!
>Close, but not quite there.
>Go for it!

I'm glad you liked it. Did you learn anything?


Henry Wilson...

........provider of free physics lessons