From: mike3 on
Hi.

Can one find an analytic solution to the recurrence functional
equation

F(z+1) = z F(z) + 2 F(z-1) - (z-4) F(z-2) - F(z-3)
F(0) = 1, F(1) = 0, F(2) = 0, F(3) = 1

in the complex z-plane? Can such a solution be expressed in closed
form using generally-accepted mathematical special functions, even if
it is not elementary? Perhaps with some kind of hypergeometric or
related thing? If such a thing is not possible, how about a Taylor
series but with explicit formulas for the coefficients?
From: mike3 on
On May 16, 8:52 pm, mike3 <mike4...(a)yahoo.com> wrote:
> Hi.
>
> Can one find an analytic solution to the recurrence functional
> equation
>
> F(z+1) = z F(z) + 2 F(z-1) - (z-4) F(z-2) - F(z-3)
> F(0) = 1, F(1) = 0, F(2) = 0, F(3) = 1
>
> in the complex z-plane? Can such a solution be expressed in closed
> form using generally-accepted mathematical special functions, even if
> it is not elementary? Perhaps with some kind of hypergeometric or
> related thing? If such a thing is not possible, how about a Taylor
> series but with explicit formulas for the coefficients?

Oops, I got the wrong initial conditions. It should be
F(0) = 2, F(1) = -1, F(2) = 0, F(3) = 1.